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我是春天的新手。我的域名是

@Document
public class Post {

     @Id
     private ObjectId _id;
     private String postTitle;
     private String postDesc;
     private ObjectId owner=Global.getCurruser();
     private List<ObjectId> intrestReceived=new ArrayList<ObjectId>();

// Getters and setters
}

我的控制器看起来像

    @RequestMapping(value = "/post/intrestReceived", method = RequestMethod.GET)
    public String intrestReceived(Model model){
        List<Post> result=postService.intrestReceived();
        model.addAttribute("result", result);
        return "intrestReceived";
    }

我的观点看起来像:

<form:form id="idForm" class="form-horizontal" method="GET">
        <table border=1>
            <tr>
                <td><b>Post ID</b></td>
                <td><b>Post Desc</b></td>
                <td><b>Intrest Received</b></td>
            </tr>
            <c:forEach items="${result}" var="result">
                <tr>
                    <td>${result.getId()}</td>
                    <td>${result.postDesc}</td>
                    <td>${result.getIntrestReceived()}</td>
                </tr>
            </c:forEach>
        </table>
    </form:form>

这里<td>${result.getIntrestReceived()}</td>返回List<ObjectId> 我如何迭代它以在单独的行中获取个人 id。对不起我的英语不好。

4

1 回答 1

1

尝试这个:

<c:forEach items="${result}" var="item">
                <tr>
                    <td>${item._id}</td>
                    <td>${item.postDesc}</td>
                  <c:forEach items="${result.intrestReceived}" var="intr">
                    <tr><td>${intr._id}</td></tr>
          </c:forEach>
                </tr>
</c:forEach>
于 2013-11-13T06:44:04.243 回答