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我的问题是我不知道实体加法器是对还是错。
我的另一个问题是我必须将实体加法器放在与实体 mult 相同的模块中？或者我应该创建另一个模块？

这是我的代码：是VHDL中两个5位数字的乘法代码。我不知道这是问题所在：库，信号或变量声明的站点，..？

`library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
use IEEE.STD_LOGIC_ARITH.ALL; 
use IEEE.NUMERIC_STD.ALL;
use UNISIM.VComponents.all;

entity mult is
   port (op1    : in  std_logic_vector(4 downto 0);--a
     op2    : in  std_logic_vector(4 downto 0);--x
     out : out std_logic_vector(9 downto 0)); --pp
end mult;

architecture Behavioral of mult is
type t_matrix is array (0 to 5, 10 downto 0) of std_logic;
signal c, sum, mul : t_matrix ;
signal sum_ini : std_logic_vector(9 downto 0) ;



begin
   rows  :  for i in 0 to 3 generate
       columns  : for j in 0 to 9 generate
           i_u : adder port map(a => sum_ini(j),
                              b =>c(i,j),
                              cin => mul(i, j),
                              sum => sum(i+1, j),
                              cout => c(i+1, j+1));
        end generate columns;
    end generate rows;

   p_multiplications : process (a, b)
   --variable v_producto : t_pp := ((others => (others => ’0’)));
   begin -- process multiplications
   for i in 0 to 4 loop
      for j in 0 to 4 loop
          if i = 0 then
            sum_ini(j) <= a(0) and b(j);
         else
            mul(i-1, j+i) <= a(i) and b(j);
         end if;
      end loop; -- j
   end loop; -- i
   end process p_multiplications;

end Behavioral;´

--I have another module my entity adder , but I don´t know where is the problem.

`entity adder is
port (  a   : in  std_logic_vector (9 downto 0));
end adder; 

architecture Behavioral of adder is 
type t_matrix is array (0 to 5, 10 downto 0) of std_logic;
signal cout, b, cin, sum  :   t_matrix  ;
begin 
sum <= (a xor cin) xor b; 
cout <= (a and b)or(cin and a)or(cin and b); 
end Behavioral;´
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1 回答 1

2

要获得“xor”和“and”运算符，请将这些行放在模块的顶部

library IEEE;
use IEEE.STD_LOGIC_1164.ALL;

另一个问题是，您无法通过采用单个位加法器的逻辑来获得 10 位加法器，而只是使信号更宽。您需要组织事物，以便位 1 的 cin 是位 0 的 cout，等等。

cin(9 downto 1) <= cout(8 downto 0);

您需要在实体加法器的端口声明中添加 b、carry_in、carry_out。

于 2013-11-12T23:07:58.983 回答