1

我需要的目标是获得最后一次回复来自用户而不是管理员并且最后一次回复是 10 天或更长时间的票。我目前有一个得到最后回复的 SQL，但我很难从管理员那里过滤用户。我当前的 SQL 是：

SELECT
    t.tid, tr.reply_date, tr.rid, u.display_name, u.user_type
FROM ticket t
JOIN (
    SELECT 
        tr_last.tid, tr_last.reply_date, tr_last.rid, tr_last.uid
    FROM ticket_reply tr_last 
    ORDER BY tr_last.reply_date DESC
) tr ON tr.tid = t.tid
LEFT JOIN user u ON u.uid = tr.uid
WHERE 
    t.status != "Closed"
    AND DATE_SUB(CURDATE(), INTERVAL 10 DAY) >= tr.reply_date
GROUP BY t.tid;

这会返回类似：

+-------+---------------------+-------+-----------------------------+-----------+
| tid   | reply_date          | rid   | display_name                | user_type |
+-------+---------------------+-------+-----------------------------+-----------+
|  6784 | 2012-03-27 04:11:52 | 40061 | (hidden)                    | admin     |
|  8094 | 2013-01-18 21:13:56 | 65037 | (hidden)                    | admin     |
|  8165 | 2012-09-10 14:59:17 | 52956 | (hidden)                    | admin     |
|  8171 | 2012-06-18 19:05:19 | 46527 | (hidden)                    | user      |
|  8313 | 2012-08-16 23:05:51 | 51362 | (hidden)                    | admin     |
|  8436 | 2012-08-16 23:20:20 | 51368 | (hidden)                    | admin     |
|  8453 | 2012-06-26 23:41:37 | 47247 | (hidden)                    | admin     |
|  8712 | 2012-11-22 10:33:05 | 59697 | (hidden)                    | user      |
|  8911 | 2013-09-24 00:52:27 | 89910 | (hidden)                    | user      |
|  8949 | 2013-09-02 16:29:22 | 87718 | (hidden)                    | user      |
+-------+---------------------+-------+-----------------------------+-----------+

如果我u.user_type = "user"在WHERE子句中添加，它会更改tr它检索到的行，因此该6784 tid行中的用户现在显示用户不是管理员，但该票证的最后回复实际上是管理员。所以这：

SELECT
    t.tid, tr.reply_date, tr.rid, u.display_name, u.user_type
FROM ticket t
JOIN (
    SELECT 
        tr_last.tid, tr_last.reply_date, tr_last.rid, tr_last.uid
    FROM ticket_reply tr_last 
    ORDER BY tr_last.reply_date DESC
) tr ON tr.tid = t.tid
LEFT JOIN user u ON u.uid = tr.uid
WHERE 
    t.status != "Closed"
    AND DATE_SUB(CURDATE(), INTERVAL 10 DAY) >= tr.reply_date
    AND u.user_type = "user"
GROUP BY t.tid;

现在返回：

+-------+---------------------+-------+-----------------------------+-----------+
| tid   | reply_date          | rid   | display_name                | user_type |
+-------+---------------------+-------+-----------------------------+-----------+
|  6784 | 2012-03-26 23:19:52 | 40051 | (hidden)                    | user      |
|  8094 | 2013-01-18 18:53:33 | 65016 | (hidden)                    | user      |
|  8165 | 2012-09-07 01:17:28 | 52831 | (hidden)                    | user      |
|  8171 | 2012-06-18 19:05:19 | 46527 | (hidden)                    | user      |
|  8313 | 2012-08-09 18:37:35 | 50776 | (hidden)                    | user      |
|  8436 | 2012-08-16 23:01:28 | 51359 | (hidden)                    | user      |
|  8453 | 2012-06-21 16:29:24 | 46843 | (hidden)                    | user      |
|  8712 | 2012-11-22 10:33:05 | 59697 | (hidden)                    | user      |
|  8911 | 2013-09-24 00:52:27 | 89910 | (hidden)                    | user      |
|  8949 | 2013-09-02 16:29:22 | 87718 | (hidden)                    | user      |
+-------+---------------------+-------+-----------------------------+-----------+

您可以注意到rid列值也不同。

所以我的问题是，我如何正确地为此返回用户？

4

1 回答 1

2

您在任何地方都没有得到最后的答复。在您的子查询中，您只是对值进行排序。

尝试这样的事情：

SELECT t.tid, tr.reply_date, tr.rid, u.display_name, u.user_type
FROM ticket t
INNER JOIN (
  SELECT tr_last.tid, tr_last.reply_date, tr_last.rid, tr_last.uid
  FROM ticket_reply tr_last
  INNER JOIN (
    SELECT tid, max(reply_date)
    FROM ticket_reply
    GROUP BY tid
    ) tr2 ON tr2.tid = tr_last.tid AND tr_last.reply_date = tr2.reply_date
  ) tr ON tr.tid = t.tid
LEFT JOIN user u ON u.uid = tr.uid AND u.user_type = "user"
WHERE t.STATUS != "Closed"
  AND DATE_SUB(CURDATE(), INTERVAL 10 DAY) >= tr.reply_date;

内部查询返回 tid 及其 MAX(date)，并给出最近的回复信息。

（我没有对此进行测试，但看起来像您正在寻找的东西）。

于 2013-11-12T17:17:37.273 回答