对不起,这可能是一个愚蠢的问题,但我是新手,我在谷歌上找不到答案。这段代码给了我两个错误:
Warning: mysql_query() expects parameter 2 to be resource, boolean given in C:\xampp\htdocs\Music Collection\submitmusic.php on line 27
Warning: mysql_error() expects parameter 1 to be resource, string given in C:\xampp\htdocs\Music Collection\submitmusic.php on line 29
不知道如何解决这个问题请帮助我。
<html>
<head>
<title> Music Collection </title>
</head>
<body>
<?php
$con = "mysql_connect ('localhost','root','','music')";
// Check Connection
if (mysql_errno())
{
echo "Failed to connect: " . mysql_error();
}
else
{
$title = $_POST['title'];
$artist = $_POST['artist'];
$album = $_POST['album'];
$location = $_POST['location'];
$media = $_POST['media'];
$sql = mysql_query("INSERT INTO entries (Title, Artist, Album, Location, Media) VALUES ('$title','$artist','$album','$location','$media')");
if (!mysql_query($con,$sql))
{
die ('Error: ' . mysql_error($con));
}
else
{
echo "record added!";
}
}
mysql_close($con);
?>
</body>
</html>