4

FileNotFoundException使用 Struts2 上传文件时奇怪。这是 JSP 的一部分：

<a:form action="/FileUploadServletAction.action" method="post" enctype="multipart/form-data">
<a:file name="fileUpload" label="File"/>
<a:submit/>

这是 execute() 方法，用于将上传的文件从临时位置复制到实际位置：

public String execute() throws Exception{
try {
        String filePath = "c:/foo";
        System.out.println("Server path:" + filePath);
        File fileToCreate = new File(filePath, this.fileUploadContentType);
        FileUtils.copyFile(this.fileUpload, fileToCreate);
    } catch (Exception e) {
        e.printStackTrace();
        addActionError(e.getMessage());
        return INPUT;
    }

    return SUCCESS;
}

这是我在上面的 Action 类中配置的 struts.xml 部分：

<action name="FileUploadServletAction"
        class="com.test.FileUploadServletAction">
        <result name="input">/jsp/upload.jsp</result>
        <result name="success">/jsp/upload.jsp</result>
        <result name="error">/jsp/error.jsp</result>
</action>

但是当我运行时，我得到了这个异常：

java.io.FileNotFoundException: Source 'E:\Foo\Projects\Foo\.metadata\.plugins\org.eclipse.wst.server.core\tmp0\work\Catalina\localhost\FooProject\upload_1ec6cc50_75d7_482f_83be_fe4185999973_00000000.tmp' does not exist
at org.apache.commons.io.FileUtils.copyFile(FileUtils.java:1074)
at org.apache.commons.io.FileUtils.copyFile(FileUtils.java:1038)

INFO: Removing file fileUpload E:\Foo\Projects\Foo\.metadata\.plugins\org.eclipse.wst.server.core\tmp0\work\Catalina\localhost\FooProject\upload_1ec6cc50_75d7_482f_83be_fe4185999973_00000000.tmp

谁能告诉我为什么 Struts 无法找到创建的临时文件？如果您需要更多信息，请告诉我。

4

2 回答 2

2

我认为您缺少 getter 和 setter 方法，我不知道您是否定义了？

JSP代码： 

<form action="FileUploadServletAction" method="post" enctype="multipart/form-data">
  <label>File:</label><input type="file" name="userKey"/>
  <input type="image" src="images/login-btn.jpg" alt="submit" width="103" height="42"/>
</form>

动作代码： 

//In FileUploadServletAction
private File userKey;  //file name which is on JSP
private String userKeyContentType;
private String userKeyFileName;  

//getter, setter  
public File getUserKey() 
{
    return userKey;
}

public void setUserKey(File userKey) 
{
    this.userKey = userKey;
}

public String getUserKeyFileName()
{
    return userKeyFileName;
} 

public String getUserKeyContentType() 
{
    return userKeyContentType;
}

public void setUserKeyContentType(String userKeyContentType)
{
    this.userKeyContentType = userKeyContentType;
}

public void setUserKeyFileName(String userKeyFileName)
{
    this.userKeyFileName = userKeyFileName;
}

现在，execute()方法

//In FileUploadServletAction
public String execute() throws Exception{
 try {
      String filePath = request.getSession().getServletContext().getRealPath("/");           
      File fileToCreate = new File(filePath, this.userKeyFileName);
      FileUtils.copyFile(this.userKey, fileToCreate);
  } catch (Exception e) {
    e.printStackTrace();
    addActionError(e.getMessage());
    return INPUT;
 }

 return SUCCESS;
}
于 2013-11-12T09:36:25.353 回答
1

尝试使用 inteceptor 你的行为应该是这样的..

 <action name="FileUploadServletAction"  class="com.test.FileUploadServletAction">
            <interceptor-ref name="fileUpload">
                <param name="maximunSize">1024000</param>
                <param name="allowedTypes">
                     your types
                </param>
            </interceptor-ref>
            <interceptor-ref name="defaultStack"></interceptor-ref>
            <result name="input">/jsp/upload.jsp</result>
            <result name="success">/jsp/upload.jsp</result>
            <result name="error">/jsp/error.jsp</result>
    </action>
于 2013-11-12T07:58:00.750 回答