我在我的代码中使用 ajax。我必须从 $('SyncDataPort0') 调用 connectHost() 到 $('SyncDataPort5'),
function connectHost()
{
ajaxFrame($('SyncDataPort0').value, getConnectStatus);
}
function getConnectStatus(transport)
{
try {
rs = transport.responseText;
if(rs == 'OK') {
//$('SyncDataState0').innerHTML = 'ok';
addStateMsg($('ConnectTest'),getMsg('msgConnectOk'));
} else //NOT OK
addStateMsg($('ConnectTest'),getMsg('msgConnectNotOkResult').replace('%s',rs));
}catch(e){alert(e)};
}
function ajaxFrame(url, pars, onCompleteFun)
{
if (3 in arguments)
addStateMsg(arguments[3],getMsg('msgDataSending'),0);
new Ajax.Request(url,
{
method:'post',
parameters:pars,
onComplete: function(transport)
{
var rs = transport.responseText;
if('logout' == rs)
location.href='/index.php?menu=logout';
else if('' == rs)
{
//do nothing
}else
onCompleteFun.apply(this,[transport]);
},
onFailure:function()
{
debug('Load Data Failure!');
}
});
return true;
}
问题是如何在不复制 getConnectStatus 回调函数的情况下实现该函数???