ios - 如何将 JSON 数据对象 POST 到服务器？

Question

我将 NSDictionary 发布到服务器并像这样获取 NSLog：

{"User":"abc@gmail.com","cartItems":[{"productName":"Apple 5s","Qty":1,"price":"1000"}],"userDiscounts":["0001"]}

但问题是当我在服务器端检查这些数据时：

{ '{"User":"abc@gmail.com","cartItems":': { '{"productName":"Apple 4s","Qty":1,"price":"1000"}],"userDiscounts"': { '"0001"]': '' } } }

我的意思是，进入 '{ and }'服务器端。这两个 json 字典有什么问题。

这是我的方法：

 // Convert object to data, cartDictionary holding data.
    NSData* postData = [NSJSONSerialization dataWithJSONObject:cartDictionary options:kNilOptions error:&error];

NSMutableURLRequest *request= [[NSMutableURLRequest alloc] init];

[request setURL:[NSURL URLWithString:combineProductUrl]];
[request setHTTPMethod:@"POST"];

[request setHTTPBody:postData];

// print json:
NSLog(@"JSON summary: %@", [[NSString alloc] initWithData:postData
                                                 encoding:NSUTF8StringEncoding]);

Answer 1

使用 NSURLConnection 的包装，即 AFNetworking https://github.com/AFNetworking/AFNetworking。根据你的问题

NSMutableDictionary *parameters = [NSMutableDictionary dictionaryWithObjectsAndKeys: deviceCode ,@"Key 1", Value 1 , @"Key 2", Value 2 , nil];

            NSLog(@"Parameter %@",parameters);

            AFHTTPClient *client = [[AFHTTPClient alloc] initWithBaseURL: [NSURL URLWithString:@"http://yourbaseURL/"]];

            [client setDefaultHeader:@"contentType" value:@"application/json; charset=utf-8"];

            client.parameterEncoding = AFJSONParameterEncoding;

            NSMutableURLRequest *request = [client requestWithMethod:@"POST" path:@"yourPostURL" parameters:parameters];

            AFJSONRequestOperation *operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:request success:^(NSURLRequest *request, NSHTTPURLResponse *response, id JSON)
                                                 {
                                                     NSLog(@"response %@",JSON);

                                                 }
                                                                                                failure:^(NSURLRequest *request, NSHTTPURLResponse *response, NSError *error, id JSON)
                                                 {
                                                     NSLog(@"request %@",[error localizedDescription]);
                                                 }];
            [operation start];

希望它可以帮助你。