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我有i代理，每个都有不同的 ip host_i。

我想提出请求

<host_i>:4444/content去

localhost:9999/content?proxy=<host_i>

我该怎么做呢？到目前为止，这是我尝试使用嵌入式码头服务器（版本：8.1.10.v20130312）的内容，但它不起作用，我无法弄清楚。我从：http ://git.eclipse.org/c/jetty/org.eclipse.jetty.project.git/tree/jetty-servlets/src/test/java/org/eclipse/jetty/servlets/得到这个例子AsyncProxyServer.java?h=jetty-8

    proxyServer = new Server();
    Connector connector = new SelectChannelConnector();
    connector.setPort(4444);
    proxyServer.setConnectors(new Connector[]{connector});

    ServletHandler handler = new ServletHandler();
    proxyServer.setHandler(handler);

    ServletHolder proxy = handler.addServletWithMapping("org.eclipse.jetty.servlets.ProxyServlet", "/");
    proxy.setAsyncSupported(true);

    proxyServer.start();

这是我使用处理请求的简单框架的代码localhost:9999：

    websiteContainer = new HttpServer();
    websiteServer = new ContainerServer(websiteContainer);
    websiteConnection = new SocketConnection(websiteServer);
    final SocketAddress websiteAddress = new InetSocketAddress(9999);
    websiteConnection.connect(websiteAddress);

    public class HttpServer implements Container {
    @Override
    public void handle(final Request request, final Response response) {
            // do some stuff here, I have a breakpoint here to test if a request to a proxy made it here
    }
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1 回答 1

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@Override
public void handle(final Request request, final Response response) {
// building redirect url localhost:9999/content?proxy=<host_i>

 redirectUrl= "localhost:9999/" + httpRequest.getContextPath() + "? proxy =" + httpRequest.getLocalAddr();            
// do remaing stuff here
}

我希望这将解决您的问题，因为httpRequest.getContextPath()它为您提供了应用程序运行位置的 IP，并httpRequest.getContextPath()为您提供了连接路径 whish 被击中

于 2013-12-23T06:30:06.947 回答