I need to get list of files in directory using APR. How can I do it? I was looking for answer in documentation, but found nothing. Thanks!
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The function you want is apr_dir_open. I found the header files to be the best documentation for APR
http://apr.apache.org/docs/apr/1.4/group_apr_dir.html
Here is an example for reading "." and reporting errors if any were encountered
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <inttypes.h>
#include <apr.h>
#include <apr_errno.h>
#include <apr_pools.h>
#include <apr_file_info.h>
static void apr_fatal(apr_status_t rv);
int main(void)
{
apr_pool_t *pool;
apr_status_t rv;
// Initialize APR and pool
apr_initialize();
if ((rv = apr_pool_create(&pool, NULL)) != APR_SUCCESS) {
apr_fatal(rv);
}
// Open the directory
apr_dir_t *dir;
if ((rv = apr_dir_open(&dir, ".", pool)) != APR_SUCCESS) {
apr_fatal(rv);
}
// Read the directory
apr_finfo_t finfo;
apr_int32_t wanted = APR_FINFO_NAME | APR_FINFO_SIZE;
while ((rv = apr_dir_read(&finfo, wanted, dir)) == APR_SUCCESS) {
printf("%s\t%10"PRIu64"\n", finfo.name, (uint64_t)finfo.size);
}
if (!APR_STATUS_IS_ENOENT(rv)) {
apr_fatal(rv);
}
// Clean up
apr_dir_close(dir);
apr_pool_destroy(pool);
apr_terminate();
return 0;
}
static void apr_fatal(apr_status_t rv)
{
const int bufsize = 1000;
char buf[bufsize+1];
printf("APR Error %d: %s\n", rv, apr_strerror(rv, buf, bufsize));
exit(1);
}
于 2014-01-05T17:15:26.790 回答