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我正在尝试将 String [] json 转换为外部服务器上的查询并显示在列表视图中

public class ConectPhp extends ListActivity {

public static InputStream inpString = null;
String result = "";

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);




    ArrayList<NameValuePair> parametros = new ArrayList<NameValuePair>();
    parametros.add(new BasicNameValuePair("DATA", "2011-11-05"));



    try{


        HttpClient httpcliente = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://192.168.254.254/mobile/ConexaoWcrm.php/");
        httppost.setEntity(new UrlEncodedFormEntity(parametros));
        HttpResponse response = httpcliente.execute(httppost);
        HttpEntity entity = response.getEntity();
        inpString = entity.getContent();

    } catch (Exception e){
        Log.e("log_tag", "Error to conect a "+e.toString());
    }

//将返回值转换为字符串

    try{
        BufferedReader reader = new BufferedReader(new InputStreamReader(inpString, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while((line = reader.readLine()) != null){
            sb.append(line+"\n");

        }
        inpString.close();
        result=sb.toString();
    }catch (Exception e){
        Log.e("log_tag","Error to convert result"+e.toString());
    }

//这里会把数据传给json，但是不知道怎么做，然后存入listview。

try{            
        JSONArray jArray = new JSONArray(result);
        String[] clientes = new String[jArray.length()];
        for(int i=0; i<jArray.length();i++){
            JSONObject json_data = jArray.getJSONObject(i);
            clientes[i]=json_data.getString("clientnome");
        }

        this.setListAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, clientes));
    }catch(Exception e){
        Log.e("log_tag","Error popular data "+e.toString());
            }

我是新手，已经有了这个困难的项目，如果他们有任何提示给我也将被接受，必须列出某些数据库用于外部列表视图。

4

2 回答 2

0

请在下面找到您发布的字符串表示的代码：-

例如，您的 jsonArray 发布在键“array”处，使用以下代码从中检索 JSONArray：-

JSONObject jObject = new JSONObject(result);//only if result is a JSONObject else get to the base of JSONObject.
JSONArray jArray = jObject.getJSONArray("array");//I suppose that "array" is the key at for your sample array you have given
//now you can run with your all other code

for(int i=0; i<jArray.length();i++)
{
    JSONObject json_data = jArray.getJSONObject(i);
    clientes[i]=json_data.getString("clientnome");
}

this.setListAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, clientes));
}
catch(Exception e)
{
    Log.e("log_tag","Error popular data "+e.toString());
}
于 2013-11-11T12:50:22.003 回答
0

这可能会帮助你...

        JSONArray array = new JSONArray(result);
        String[] strings = new String[array.length()];
        for (int i = 0; i < array.length(); i++) {
            Object object = array.get(i);
            if (object instanceof JSONObject) {
                JSONObject jsonObject = (JSONObject) object;
                strings[i] = jsonObject.getString("clientnome");
            }
        }
于 2013-11-11T13:11:32.800 回答