我正在尝试通过 C API 使用 Clang,索引要详细。问题是某些类型不是按其编写的方式返回,而是按它们用于编译器的方式返回。例如,“Stream &”变成“int &”,“byte”变成“int.
一些测试库:
// TODO make it a subclass of a generic Serial/Stream base class
class FirmataClass
{
public:
FirmataClass(Stream &s);
void setFirmwareNameAndVersion(const char *name, byte major, byte minor);
我正在使用代码来获取方法信息:
void showMethodInfo(const CXIdxDeclInfo *info) {
int numArgs = clang_Cursor_getNumArguments(info->cursor);
fprintf(stderr, " %i args:\n", numArgs);
for (int i=0; i<numArgs; i++) {
CXCursor argCursor = clang_Cursor_getArgument(info->cursor, i);
CXString name = clang_getCursorDisplayName(argCursor);
CXString spelling = clang_getCursorSpelling(argCursor);
CXType type = clang_getCursorType(argCursor);
CXString typeSpelling = clang_getTypeSpelling(type);
CXCursorKind kind = clang_getCursorKind(argCursor);
fprintf(stderr, " kind=[%s (%i)], type=[%s], spelling=[%s]\n",
cursor_kinds[kind], kind, clang_getCString(typeSpelling),
clang_getCString(spelling));
clang_disposeString(name);
clang_disposeString(spelling);
clang_disposeString(typeSpelling);
}
// return type
CXType returnType = clang_getCursorResultType(info->cursor);
CXString returnTypeSpelling = clang_getTypeSpelling(returnType);
fprintf(stderr, " returns %s\n", clang_getCString(returnTypeSpelling));
clang_disposeString(returnTypeSpelling);
}
输出:
[105:10 4689] access=[CX_CXXPublic] kind=[CXIdxEntity_CXXInstanceMethod] (21) name=[setFirmwareNameAndVersion] is_container=[0] 3 args:
kind=[CXCursor_ParmDecl (10)], type=[const char *], 拼写=[name]
kind=[CXCursor_ParmDecl (10)], type=[int], spelling=[major]
kind=[CXCursor_ParmDecl (10)], type=[int], spelling=[minor] 返回 void
所以你可以看到byte
函数参数被描述为int
。我怎样才能得到实际的拼写?