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您好，我需要按特定时间段对数据进行分组的最佳解决方案。我需要将月份数据从 07:00:00 到 18:59:59 分组，然后从 19:00:00 到第二天 06:59:59。在数据库中有大量数据，因此首选快速有效的解决方案。

在查询中插入 Shift 字母也很好。有 4 个班次：A、B、C、D，我有日历表。

Table [Shiftcalendar]:
[ShiftDate] | [SHIFT] | [Nextshift]
2013-11-11  |    N    |     A=B
2013-11-11  |    D    |     C=A
2013-11-10  |    N    |     D=C
....        |   ....  |    ....

[Shift] 列代表白天或夜晚，[Nextshift] 列代表班次和下一班次。N 表示夜间，从 19:00:00 到次日 06:59:59，D 表示白天，从 07:00:00 到 18:59:59。

Table [wrkSpeedInfo]:
[wrkActionDate]     | [wrkSpeed] | [wrkGlueValue] | [x1]
2013-11-11 07:00:35 |     200    |       300      |  20
2013-11-11 07:00:55 |     97     |       255      |  13
2013-11-11 07:01:23 |     127    |       124      |  15
....                |     ....   |       ....     | ....

我需要对 [wrkSpeed]、[wrkGlueValue] 和 [x1] 求和。

有人的帮助将不胜感激:)

PS.：别介意我的英语写作能力，我还在提高它的边缘。

编辑：这么长时间以来，我做了很多查询来获取特定的日期和班次数据，但希望在一个查询中包含所有数据。

WHERE [wrkActionDate] BETWEEN '2013-10-03 07:00:00' AND '2013-10-03 18:59:59'

我可以发布完整的查询，但它需要很多空间，什么时候需要解释更多我想要做的事情。

编辑：好的，有人说要发布完整的查询：

SELECT [wrkActionDate]
  ,[wrkCntrId]
  ,DATEDIFF(second, (SELECT TOP 1 t2.[wrkActionDate] FROM [DW].[dbo].[wrkSpeedInfo] as t2 WHERE [wrkCntrId] = 'S1' AND t2.[wrkActionDate] < t1.[wrkActionDate]  ORDER BY t2.[wrkActionDate] DESC), [wrkActionDate])/60.0 AS MinPassed
  ,SUM([wrkSpeed])*DATEDIFF(second, (SELECT TOP 1 t2.[wrkActionDate] FROM [DW].[dbo].[wrkSpeedInfo] as t2 WHERE [wrkCntrId] = 'S1' AND t2.[wrkActionDate] < t1.[wrkActionDate]  ORDER BY t2.[wrkActionDate] DESC), [wrkActionDate])/60.0 AS SumWrkSpeed
  ,SUM([wrkGlueValue])*DATEDIFF(second, (SELECT TOP 1 t2.[wrkActionDate] FROM [DW].[dbo].[wrkSpeedInfo] as t2 WHERE [wrkCntrId] = 'S1' AND t2.[wrkActionDate] < t1.[wrkActionDate]  ORDER BY t2.[wrkActionDate] DESC), [wrkActionDate])/60.0 AS SumWrkGlueValue
  ,SUM([x1]) AS SumX1
FROM [DW].[dbo].[wrkSpeedInfo] as t1
WHERE [wrkActionDate] BETWEEN '2013-10-03 07:00:00' AND '2013-10-03 18:59:59' AND [wrkCntrId] = 'S1'
GROUP BY [wrkCntrId], [wrkActionDate]

因此，如果我可以在一个查询中获取所有月份的数据，那就太好了，因为现在只获取一个班次的数据。

得到类似的东西会很棒：

[ShiftDate] | [SHIFT] | [Nextshift] | SUM([wrkSpeed]) | SUM([wrkGlueValue]) | SUM([x1])

编辑：他们使用 MS SQL 2012。不能改变结构或任何东西，只能从数据库中选择数据。

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1 回答 1

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如果您想仅根据日期对所有值求和，则只需 GROUP BY CAST(wrkActionDate AS DATE)

但是你不想精确地按日期分组，你想根据你的班次模式进行分组。因此，您可以创建一个字段来计算特定时间落入哪个班次，然后根据该字段进行分组。

SELECT [Shift]
    ,SUM(wrkSpeed) AS wrkSpeed
    ,SUM(wrkGlueValue) AS wrkGlueValue
    ,SUM(x1) AS x1
FROM(
    SELECT w.*,
        CASE WHEN (DATEPART(HOUR, wrkActionDate) >= 7 AND DATEPART(HOUR, wrkActionDate) < 19) 
                THEN LEFT(CAST(wrkActionDate AS DATE),10)+' D' 
                ELSE LEFT(CAST(DATEADD(DAY, -1, wrkActionDate) AS DATE),10)+' N' 
           END AS [Shift]
    FROM [DW].[dbo].wrkSpeedInfo w
) w
GROUP BY [Shift]
于 2013-11-11T12:26:57.637 回答