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我有这个问题:我有一群人分为 5 个年龄组。最初他们都是易感的,然后他们患上了疾病,最后他们患上了癌症。我有关于易感人群和癌症携带者年龄组分布的信息。在易感状态和癌症之间,它们经历了7个阶段,具有相同的转变率。我正在尝试创建一个模型,将每个转换模拟为二项式提取并拟合我拥有的数据。我尝试了一些东西,但在分析痕迹的那一刻,没有任何工作你可以看到代码我哪里出错了?谢谢你的帮助

from pylab import *
from pymc import *
from pymc.Matplot import plot as plt 

#susceptible_data = array([647,1814,8838,9949,1920])
susceptible_data = array([130,398,1415,1303,206])
infected_data_100000 = array([0,197,302,776,927])
infected_data = array([0,7,38,90,17])
prior_values=np.zeros(len(infected_data))
for i in range(0,len(infected_data)):
    prior_values[i]=infected_data[i]/susceptible_data[i]
# stochastic priors


beta1 = Uniform('beta1', 0., 1.)




lambda_0_temp=susceptible_data[0]
lambda_0_1=pymc.Binomial("lambda_0_1",lambda_0_temp,pow(beta1,1))
lambda_0_2=pymc.Binomial("lambda_0_2",lambda_0_1.value,pow(beta1,1))
lambda_0_3=pymc.Binomial("lambda_0_3",lambda_0_2.value,pow(beta1,1))
lambda_0_4=pymc.Binomial("lambda_0_4",lambda_0_3.value,pow(beta1,1))
lambda_0_5=pymc.Binomial("lambda_0_5",lambda_0_4.value,pow(beta1,1))
lambda_0_6=pymc.Binomial("lambda_0_6",lambda_0_5.value,pow(beta1,1))
lambda_0_7=pymc.Binomial("lambda_0_7",n=lambda_0_6.value,p=pow(beta1,1),value=infected_data[0],observed=True)

lambda_1_temp=susceptible_data[1]
lambda_1_1=pymc.Binomial("lambda_1_1",lambda_1_temp,pow(beta1,1))
lambda_1_2=pymc.Binomial("lambda_1_2",lambda_1_1.value,pow(beta1,1))
lambda_1_3=pymc.Binomial("lambda_1_3",lambda_1_2.value,pow(beta1,1))
lambda_1_4=pymc.Binomial("lambda_1_4",lambda_1_3.value,pow(beta1,1))
lambda_1_5=pymc.Binomial("lambda_1_5",lambda_1_4.value,pow(beta1,1))
lambda_1_6=pymc.Binomial("lambda_1_6",lambda_1_5.value,pow(beta1,1))
lambda_1_7=pymc.Binomial("lambda_1_7",n=lambda_1_6.value,p=pow(beta1,1),value=infected_data[1],observed=True)

lambda_2_temp=susceptible_data[2]
lambda_2_1=pymc.Binomial("lambda_2_1",lambda_2_temp,pow(beta1,1))
lambda_2_2=pymc.Binomial("lambda_2_2",lambda_2_1.value,pow(beta1,1))
lambda_2_3=pymc.Binomial("lambda_2_3",lambda_2_2.value,pow(beta1,1))
lambda_2_4=pymc.Binomial("lambda_2_4",lambda_2_3.value,pow(beta1,1))
lambda_2_5=pymc.Binomial("lambda_2_5",lambda_2_4.value,pow(beta1,1))
lambda_2_6=pymc.Binomial("lambda_2_6",lambda_2_5.value,pow(beta1,1))
lambda_2_7=pymc.Binomial("lambda_2_7",n=lambda_2_6.value,p=pow(beta1,1),value=infected_data[2],observed=True)

lambda_3_temp=susceptible_data[3]
lambda_3_1=pymc.Binomial("lambda_3_1",lambda_3_temp,pow(beta1,1))
lambda_3_2=pymc.Binomial("lambda_3_2",lambda_3_1.value,pow(beta1,1))
lambda_3_3=pymc.Binomial("lambda_3_3",lambda_3_2.value,pow(beta1,1))
lambda_3_4=pymc.Binomial("lambda_3_4",lambda_3_3.value,pow(beta1,1))
lambda_3_5=pymc.Binomial("lambda_3_5",lambda_3_4.value,pow(beta1,1))
lambda_3_6=pymc.Binomial("lambda_3_6",lambda_3_5.value,pow(beta1,1))
lambda_3_7=pymc.Binomial("lambda_3_7",n=lambda_3_6.value,p=pow(beta1,1),value=infected_data[3],observed=True)

lambda_4_temp=susceptible_data[4]
lambda_4_1=pymc.Binomial("lambda_4_1",lambda_4_temp,pow(beta1,1))
lambda_4_2=pymc.Binomial("lambda_4_2",lambda_4_1.value,pow(beta1,1))
lambda_4_3=pymc.Binomial("lambda_4_3",lambda_4_2.value,pow(beta1,1))
lambda_4_4=pymc.Binomial("lambda_4_4",lambda_4_3.value,pow(beta1,1))
lambda_4_5=pymc.Binomial("lambda_4_5",lambda_4_4.value,pow(beta1,1))
lambda_4_6=pymc.Binomial("lambda_4_6",lambda_4_5.value,pow(beta1,1))
lambda_4_7=pymc.Binomial("lambda_4_7",n=lambda_4_6.value,p=pow(beta1,1),value=infected_data[4],observed=True)

model=pymc.Model([lambda_0_7,lambda_1_7,lambda_2_7,lambda_3_7,lambda_4_7,beta1])
mcmc =pymc.MCMC(model)
mcmc.sample(iter=100000, burn=50000, thin=10, verbose=1)


lambda_0_samples=mcmc.trace('lambda_0_7')[:]
lambda_1_samples=mcmc.trace('lambda_1_7')[:]
lambda_2_samples=mcmc.trace('lambda_2_7')[:]
lambda_3_samples=mcmc.trace('lambda_3_7')[:]
lambda_4_samples=mcmc.trace('lambda_4_7')[:]
beta1_samples=mcmc.trace('beta1')[:]
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1 回答 1

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您在上面实现的仅将数据与每组中的第 7 个分布相关联;其他的似乎是二项式概率的冗余层次结构。我认为您希望数据通知每个阶段。我不确定是否有信息可以根据所提供的信息来告知每个阶段 p 的值应该是什么。

于 2013-11-13T17:42:49.197 回答