我正在尝试在自动完成框中显示 POST-CODE 信息。
例如:如果用户查看地址:25 Cordwallis Road,Madienhead,SL6 7DQ... 它也可以检索邮政编码。
function initialize() {
directionsDisplay = new google.maps.DirectionsRenderer();
var heathrow = new google.maps.LatLng(51.4706001282,-0.461941003799);
var mapOptions = {
center: heathrow,
zoom:14,
mapTypeId: google.maps.MapTypeId.ROADMAP
};
map = new google.maps.Map(document.getElementById('map-canvas'), mapOptions);
directionsDisplay.setMap(map);
var inputFrom =(document.getElementById('searchFrom'));
var options = {
componentRestrictions: {country: "US"}
};
var autocompleteFrom = new google.maps.places.Autocomplete(inputFrom, options);
var infowindow = new google.maps.InfoWindow();
var marker = new google.maps.Marker({
map: map
});
google.maps.event.addListener(autocompleteFrom, 'place_changed', function() {
infowindow.close();
marker.setVisible(false);
inputFrom.className = '';
var place = autocompleteFrom.getPlace();
if (!place.geometry) {
// Inform the user that the place was not found and return.
inputFrom.className = 'notfound';
return;
}
// If the place has a geometry, then present it on a map.
if (place.geometry.viewport) {
map.fitBounds(place.geometry.viewport);
} else {
map.setCenter(place.geometry.location);
map.setZoom(17); // Why 17? Because it looks good.
}
marker.setIcon(/** @type {google.maps.Icon} */({
url: place.icon,
size: new google.maps.Size(71, 71),
origin: new google.maps.Point(0, 0),
anchor: new google.maps.Point(17, 34),
scaledSize: new google.maps.Size(35, 35)
}));
marker.setPosition(place.geometry.location);
marker.setVisible(true);
var address = '';
if (place.address_components) {
address = [
(place.address_components[0] && place.address_components[0].short_name || ''),
(place.address_components[1] && place.address_components[1].short_name || ''),
(place.address_components[2] && place.address_components[2].short_name || '')
].join(' ');
}
infowindow.setContent('<div><strong>' + place.name + '</strong><br>' + address);
infowindow.open(map, marker);
calcRoute();
});
我如何使用它来获取邮政编码信息
var zip = address[address.length - 1].long_name = results[0].address_components;
任何人都可以提出想法