6

我从以下代码发布用户输入时遇到问题。仅在单击提交按钮两次后才会发布信息。请查看我的代码并告诉我是否需要更改任何内容。

<script>
function validate(form) {
    fail = validateName(form.name.value)
    fail += validateEmail(form.email.value)
    fail += validateCity(form.city.value)
    if (fail == "") {
        $(function () {
            $('#submitbtn').click(function (event) {
                event.preventDefault();
                var form = $(this).closest('form'),
                    action = form.attr('action');
                $.post(action, form.serialize(), function (data) {
                    $('#errors').html("You have been successfully subscribed to our newsletter.");
                })
            });
        });
    }
    else {
        document.getElementById('errors').innerHTML = fail;
    }
    return false
}
function validateName(field) {
    if (field == "") return "No name was entered.<br/>"
    else if (field.length < 3) return "Please enter a valid name.<br/>"
    else if (!/[a-zA-Z ]/.test(field)) return "Name can only have alphabetical characters.<br/>"
    return ""
}

function validateEmail(field) {
    if (field == "") return "No email was entered.<br/>"
    else if (!((field.indexOf(".") > 0) && (field.indexOf("@") > 0)) || /[^a-zA-Z0-9.@_-]/.test(field)) return "The email address is invalid.<br/>"
    return ""
}

function validateCity(field) {
    if (field == "") return "No city was entered.<br/>"
    else if (field.length < 3) return "Please enter a valid city.<br/>"
    else if (!/[a-zA-Z ]*$/.test(field)) return "City can only have alphabetical characters.<br/>"
    return ""
}
            
</script>


</head>

<body id="body-results-page">
    <div class="modalDialog" id="openModal">
        <div>
            <a class="close" href="#close" title="Close">X</a>
            
     <h2>Newsletter Sign-Up</h2>      

  <form action="" name="subscribe1" id="subscribe1" method="POST" autocomplete="off" onSubmit="return validate(this)">
<div id="errors"></div>
<input name="name" required pattern="[a-zA-Z ]*$" title="Please enter only alphabetic characters" type="text" id="name" placeholder="Your name"/>


<input name="email" required id="email" type="email" title="Please enter your email address" placeholder="Your email address"/>

<input name="city" required pattern="[a-zA-Z ]*$" title="Please enter only alphabetic characters" id="city" placeholder="Your city"/>

<div id="buttons">
            <input type="reset" name="reset" id="resetbtn" class="resetbtn" value="Reset"/>
            
            <button type="submit" name="submit" id="submitbtn" class="submitbtn" value="Submit this!">Subscribe Now!</button>
            
            <br style="clear:both;">
        </div>
<input type="hidden" name="MM_insert" value="subscribe1">
  </form>
4

2 回答 2

1

因为您validate(form)在提交时调用函数并将提交处理程序添加到按钮之后但不调用它。

解决方案 - 将单击提交处理程序附加到按钮后调用提交处理程序。

$('#submitbtn').click();

像这样

if (fail == "") {
    $(function () {
        $('#submitbtn').click(function (event) {
            event.preventDefault();
            var form = $(this).closest('form'),
                action = form.attr('action');
            $.post(action, form.serialize(), function (data) {
                $('#errors').html("You have been successfully subscribed to our newsletter.");
            })
        }).click();
    });
}

或者

如果条件为 true ，最好不要附加提交处理程序，直接运行 AJAX 请求。

像这样

if (fail == "") {
        action = $(form).attr('action');
    $.post(action, $(form).serialize(), function (data) {
        $('#errors').html("You have been successfully subscribed to our newsletter.");
    })
}
于 2013-11-11T06:47:50.653 回答
0

您不需要绑定提交处理程序。当您在validate(form)函数中执行验证时。

所以而不是

if (fail == "") {
    $(function () {
        $('#submitbtn').click(function (event) {
            event.preventDefault();
            var form = $(this).closest('form'),
                action = form.attr('action');
            $.post(action, form.serialize(), function (data) {
                $('#errors').html("You have been successfully subscribed to our newsletter.");
            })
        });
    });
}

只需使用

if (fail == "") {
    var form = $(this).closest('form'),
        action = form.attr('action');
    $.post(action, form.serialize(), function (data) {
        $('#errors').html("You have been successfully subscribed to our newsletter.");
    })
}
于 2013-11-11T06:53:28.850 回答