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爪哇。将字符串转换为其等效的 ASCII 代码，并且：

public class Loop {
    public static void main (String[] args) {
        BralecPodatkov bp = new BralecPodatkov();     // allows me to write string
        System.out.println("Type string: ");
        String niz = bp.beriNiz();                    // reads my string
        int[] frequencies = new int [128];     // all 128 ASCII signs
        int total = 0;

        System.out.println("N of signs: " + niz.length());     // sum of all signs

        for (int i = 0; i < niz.length(); i++) {
            int ascii = (int) niz.charAt(i);
                frequencies[ascii]++;
                total += 1;
        }

        for (int i = 0; i < frequencies.length; i++) {
            if (frequencies[i] > 0)
                System.out.print(" " + (((float) frequencies[i]/total)*100) + "%");
          else
                System.out.print(" 0%");     // prints all sign frequencies in %
        }               

        int max = frequencies[0];
        for (int i = 0; i < niz.length(); i++) {
            if (frequencies[i] > max) {
                max = frequencies[i];     // print sign with highest frequency
            }
        }
    System.out.println("\n" + "Max number: " + max);     
    }
}

结果：

Type string: 
1234               // arbitrary string that I insert
N of signs: 4
 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 25.0% 25.0% 25.0% 25.0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0%
Max number: 0

读取字符串并打印出的代码：所有符号的总和、每个符号的频率（以 % 为单位）和频率最高的符号。问题：
1）如何在每个频率之前添加适当的符号？（例如 1 = 25%, 2 = 25%, ...）
2) 我的最大数字频率代码不起作用，它总是打印出 0。我做错了什么？
3）如何计算字符串的唯一符号数？

此外，如果您发现任何错误、并发症或有任何意见，请告诉我。

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1 回答 1

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1 -在 java 中将 int 流转换为 char之前已回答

for (int i = 0; i < frequencies.length; i++) {
        System.out.print( Character.toChars(i) );
        System.out.print( " = ");
        if (frequencies[i] > 0)

2 - 最大计数有错字：

    int max = frequencies[0];
    for (int i = 0; i < niz.length(); i++) {

使用frequencies.length而不是 niz.length()。

3 - 不确定你在问什么。输入字符串中的唯一字符？看看frequencies[i] > 0在最大循环中是否可行。

于 2013-11-10T17:44:07.610 回答