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我是neo4j的新手。对于我的要求，我需要获取 ids(collect) 列表并在同一查询中删除节点。

在下面的查询中，当我只返回 id 时，我得到了正确的结果，即；2个ID

START n=node:galleryid(galleryid='f0666ac5-9f61-4431-80b1-c9719ef8c1f9') 
MATCH n-[rels*1..]->p 
WITH n, rels, p, collect(p.photouniqueid) as photoids 
RETURN photoids;

结果符合预期并得到它：["3dcd792b-9eed-4a74-826a-6801c9f2b707"] ["e5c91a60-41cf-4afb-8aa6-49a4af00dd38"]

但是当我尝试将删除子句附加到查询时，我只得到一个 id。

START n=node:galleryid(galleryid='f0666ac5-9f61-4431-80b1-c9719ef8c1f9') 
MATCH n-[rels*1..]->p WITH n, rels, p, collect(p.photouniqueid) as photosid 
FOREACH(rel IN rels: DELETE rel) 
DELETE p 
WITH n, photosid 
MATCH n<-[r]-() 
DELETE n, r 
RETURN photosid;

Result - ["3dcd792b-9eed-4a74-826a-6801c9f2b707"]
==> 1 row
==> Nodes deleted: 3
==> Relationships deleted: 3

有人可以建议第二个查询有什么问题吗？谢谢您的帮助。

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1 回答 1

1

尝试这个：

START n=node:galleryid(galleryid='f0666ac5-9f61-4431-80b1-c9719ef8c1f9') 
MATCH n-[rels*1..]->p 
WITH n, collect(path as paths) collect(p.photouniqueid) as photosid 
FOREACH(p IN paths: 
  FOREACH(r in rels(p) :  DELETE rel)
  FOREACH(x in tail(nodes(p)) : DELETE x)
)
WITH n, photosid
MATCH n<-[r]-() 
DELETE n, r 
RETURN photosid;

如果第二次匹配没有找到任何路径，则不会返回任何内容

于 2013-11-10T06:26:13.700 回答