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if(move_uploaded_file($_FILES[$thumbnail_fieldname]['tmp_name'], $thumbnail_filename) &&
    //move desktop files
    move_uploaded_file($_FILES[$desktop_fieldname_1280x800]['tmp_name'], $desktop_filename_1280x800) &&
    move_uploaded_file($_FILES[$desktop_fieldname_1366x768]['tmp_name'], $desktop_filename_1366x768) &&
    move_uploaded_file($_FILES[$desktop_fieldname_1920x1080]['tmp_name'], $desktop_filename_1920x1080)){

    echo "<p>We can move all files.</p>";}

In my code above the text is not printed when one of the conditions fail, and that is because of && which means all needs to be true, what I want to achieve here is when any of the file is selected to upload it should go through条件并打印文本，如果没有选择任何一个或两个文件，它可以跳过并仍然打印文本，因为一个文件存在，如果没有选择文件，则条件应该为假。它不能用 || 完成 因为如果一个是真的，一切都是真的，那么可以使用什么组合来做到这一点？

例如缩略图文件已移动 = ture

桌面文件 1280x800 已移动 = 真的

桌面文件 1366x768未移动= false //从这里它应该测试下一个条件

桌面文件 1920x1080 已移动 = true

//并且应该打印输出。

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1 回答 1

3

那这个呢：

// trys to upload the thumbnail
if(move_uploaded_file($_FILES[$thumbnail_fieldname]['tmp_name'], $thumbnail_filename)
  // and tries to upload all the other images and store the return values.  
  // if one or more of them succeeded print the message
  && in_array(TRUE, array(
    move_uploaded_file($_FILES[$desktop_fieldname_1280x800]['tmp_name'], $desktop_filename_1280x800),
    move_uploaded_file($_FILES[$desktop_fieldname_1366x768]['tmp_name'], $desktop_filename_1366x768),
    move_uploaded_file($_FILES[$desktop_fieldname_1920x1080]['tmp_name'],$desktop_filename_1920x1080)
))) {
    echo 'upload done';
} else {
    echo 'no upload happened';
}
于 2013-11-09T14:18:02.387 回答