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我无法使用连接产生预期的结果。

我在 Windows 7 64 位上运行 GNUwin32。我正在运行 join 版本 5.3.0.1936 和 gawk 版本 3.1.6.2962。

输入以下两个表：

表格1

UID_C   CID
C000002 31799
C000002 31800
C000386 14950
C000386 9807916
C000386 10255083
C008114 5318432
C008117 799
C008117 444150
C008117 46878464

表_2

UID_C   CID name
C000002 31799   bevonium
C000002 31800   bevonium
C002284 24832095    hypromellose
C008117 799 indoleglycerol phosphate
C008117 444150  indoleglycerol phosphate
C008117 46878464    indoleglycerol phosphate

我在 bat 文件中使用以下命令：

C:\gnuwin32\bin\join -t"|" -1 1 -2 1 -a1 -a2 -e "NULL" -o "0,1.2,2.2,2.3" C:\directory\Table_1.txt C:\directory\Table_2.txt > C:\directory\Table_3.txt

在我关于 stackoverflow 的插图中，表格使用制表符进行格式化以便于阅读，但实际上我使用管道作为输入和输出分隔符。

输出下表：

表3

UID_C   CID CID name
C000002 31800   31799   bevonium
C000002 31800   31800   bevonium
C000002 31799   31799   bevonium
C000002 31799   31800   bevonium
C000386 10255083    NULL    NULL
C000386 9807916 NULL    NULL
C000386 14950   NULL    NULL
C002284 NULL    24832095    hypromellose
C008114 5318432 NULL    NULL
C008117 46878464    799 indoleglycerol phosphate
C008117 46878464    444150  indoleglycerol phosphate
C008117 46878464    46878464    indoleglycerol phosphate
C008117 444150  799 indoleglycerol phosphate
C008117 444150  444150  indoleglycerol phosphate
C008117 444150  46878464    indoleglycerol phosphate
C008117 799 799 indoleglycerol phosphate
C008117 799 444150  indoleglycerol phosphate
C008117 799 46878464    indoleglycerol phosphate

所需的输出是：

表_4

UID_C   CID name
C000002 31799   bevonium
C000002 31800   bevonium
C000386 14950   NULL
C000386 9807916 NULL
C000386 10255083    NULL
C002284 24832095    hypromellose
C008114 5318432 NULL
C008117 799 indoleglycerol phosphate
C008117 444150  indoleglycerol phosphate
C008117 46878464    indoleglycerol phosphate

如何更改连接命令以产生所需的输出？

或者，我应该如何使用 awk 作为 Table_3 的后处理来生成 Table_4？

提前感谢您的建议。

4

1 回答 1

2

我认为您需要比加入provide更多的逻辑：

awk -F"|" -v "OFS=|" '
    NR==FNR {uid_cid[$1 OFS $2]=1; next}
    { 
        key = $1 OFS $2
        if (key in uid_cid) {
            delete uid_cid[key]
        }
        print
    }
    END {
        for (key in uid_cid) {
            print key, "NULL"
        }
    }
' Table_1 Table_2 | sort -k1,1 -k2,2n -t "|"

C000002|31799|bevonium
C000002|31800|bevonium
C000386|14950|NULL
C000386|9807916|NULL
C000386|10255083|NULL
C002284|24832095|hypromellose
C008114|5318432|NULL
C008117|799|indoleglycerol phosphate
C008117|444150|indoleglycerol phosphate
C008117|46878464|indoleglycerol phosphate
于 2013-11-09T14:08:28.653 回答