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我有一个显示海拔的代码和另一个显示天气信息的代码。有没有办法将这两个代码合并在一起，所以我有一张同时具有这两种功能的地图？我正在使用记事本来解决这个问题。

代码 1：

    <!DOCTYPE html>
    <html>
    <head>
    <meta name="viewport" content="initial-scale=1.0, user-scalable=no">
    <meta charset="utf-8">
    <title>Elevation service</title>
    <style>
      html, body, #map-canvas {
        height: 100%;
        margin: 0px;
        padding: 0px
      }
    </style>
    <script src="https://maps.googleapis.com/maps/api/js?v=3.exp&sensor=false"></script>
    <script>

    var weatherLayer = new google.maps.weather.WeatherLayer({
    temperatureUnits: google.maps.weather.TemperatureUnit.CELSIUS
    });
    weatherLayer.setMap(map);

    var cloudLayer = new google.maps.weather.CloudLayer();
    cloudLayer.setMap(map);
    }
   var elevator;
   var map;
   var infowindow = new google.maps.InfoWindow();
   var denali = new google.maps.LatLng(60.750000, -139.500000);

   function initialize() {
   var mapOptions = {
    zoom: 8,
    center: denali,
    mapTypeId: 'terrain'
    }
    map = new google.maps.Map(document.getElementById('map-canvas'), mapOptions);

     // Create an ElevationService
    elevator = new google.maps.ElevationService();

    // Add a listener for the click event and call getElevation on that location
    google.maps.event.addListener(map, 'click', getElevation);
    }

    function getElevation(event) {

    var locations = [];

    // Retrieve the clicked location and push it on the array
    var clickedLocation = event.latLng;
    locations.push(clickedLocation);

    // Create a LocationElevationRequest object using the array's one value
   var positionalRequest = {
    'locations': locations
    }

    // Initiate the location request
    elevator.getElevationForLocations(positionalRequest, function(results, status) {
    if (status == google.maps.ElevationStatus.OK) {

      // Retrieve the first result
      if (results[0]) {

        // Open an info window indicating the elevation at the clicked position
        infowindow.setContent('The elevation at this point <br>is ' + results[0].elevation + ' meters.');
        infowindow.setPosition(clickedLocation);
        infowindow.open(map);
      } else {
        alert('No results found');
      }
    } else {
      alert('Elevation service failed due to: ' + status);
    }
  });
}
google.maps.event.addDomListener(window, 'load', initialize);
    </script>
  </head>
  <body>
    <div id="map-canvas"></div>
  </body>
</html>

和代码 2：

<!DOCTYPE html>
<html>
  <head>
    <meta charset="utf-8">
    <title>Weather layer</title>
    <style>
      html, body, #map-canvas {
        height: 100%;
        margin: 0px;
        padding: 0px
      }
    </style>
    <script src="https://maps.googleapis.com/maps/api/js?v=3.exp&sensor=false&libraries=weather"></script>
    <script>
function initialize() {
  var mapOptions = {
    zoom: 8,
    center: new google.maps.LatLng(60.750000, -139.500000),
    mapTypeId: google.maps.MapTypeId.TERRAIN
  };

  var map = new google.maps.Map(document.getElementById('map-canvas'),
      mapOptions);

  var weatherLayer = new google.maps.weather.WeatherLayer({
    temperatureUnits: google.maps.weather.TemperatureUnit.CELSIUS
  });
  weatherLayer.setMap(map);

  var cloudLayer = new google.maps.weather.CloudLayer();
  cloudLayer.setMap(map);
}

google.maps.event.addDomListener(window, 'load', initialize);

    </script>
  </head>
  <body>
    <div id="map-canvas"></div>
  </body>
</html>
4

1 回答 1

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您可能希望将代码放入单独的 .js 文件中，并将其链接到其中。这样，代码将彼此相邻，因此您可以获得两种效果，否则将无法正常工作。您已经从 google 链接了一个脚本文件 - 您只需将您的代码放入 .js 文件中，并以相同的方式链接它

于 2013-11-09T00:55:27.360 回答