如何根据时间字符串对这样的多维列表进行排序?子列表可以有不同的大小(即 4 和 5,此处)
我想通过比较每个子列表(子列表 [-4])中的第一个时间字符串进行排序
x =
(['1513', '08:19PM', '10:21PM', 1, 4],
['1290', '09:45PM', '11:43PM', 1, 4],
['0690', '07:25AM', '09:19AM', 1, 4],
['0201', '08:50AM', '10:50AM', 1, 4],
['1166', '04:35PM', '06:36PM', 1, 4],
['0845', '05:40PM', '07:44PM', 1, 4],
['1267', '07:05PM', '09:07PM', 1, 4],
['1513', '08:19PM', '10:21PM', 1, 4],
['1290', '09:45PM', '11:43PM', 1, 4],
['8772', '0159', '12:33PM', '02:43PM', 1, 5],
['0888', '0570', '09:42PM', '12:20AM', 1, 5],
['2086', '2231', '04:10PM', '06:20PM', 1, 5])
排序的结果将是
sortedX =
(['0690', '07:25AM', '09:19AM', 1, 4],
['0201', '08:50AM', '10:50AM', 1, 4],
['1166', '04:35PM', '06:36PM', 1, 4],
['0845', '05:40PM', '07:44PM', 1, 4],
['1267', '07:05PM', '09:07PM', 1, 4],
['1513', '08:19PM', '10:21PM', 1, 4],
['1513', '08:19PM', '10:21PM', 1, 4],
['1290', '09:45PM', '11:43PM', 1, 4],
['1290', '09:45PM', '11:43PM', 1, 4],
['8772', '0159', '12:33PM', '02:43PM', 1, 5],
['2086', '2231', '04:10PM', '06:20PM', 1, 5],
['0888', '0570', '09:42PM', '12:20AM', 1, 5])
我尝试了以下方法:
sortedX = sorted(x, key=lambda k : k[-4]) #k[-4] is the first time string
它可以工作,但它不尊重子列表大小排序