1

在此查询中，我希望返回总共 x 条记录。在该查询中，我有几个子查询，我无法确定它们是否会返回最大记录数。如果一个结果小于它的最大限制，我想用下一个查询填充剩余的插槽，依此类推。我无法在限制子句中进行数学运算，所以我仍在试图弄清楚如何去做。如果在 limit 子句中可以使用数学，我会这样做。

select *
from 
(
(select * from profile where size='local' order by rand() limit 7) as local 
join 
(select * from profile where size='regional' order by rand() limit (13-count(local.id)) as regional
join 
(select * from profile where size='national' order by rand() limit (19-(count(local.id)+count(regional.id))) as national
join 
(select * from profile where size='international' order by rand() limit (25-(count(local.id)+count(regional.id)+count(national.id)))) as international    
)
4

1 回答 1

1

我可能以一种不必要的复杂方式做到了这一点，但它似乎确实有效：-

SELECT id, size
FROM
(
    SELECT id, size, 
        @SeqLocal:=IF(size="local", IF(@SeqLocal <= 7, @SeqLocal + 1, @SeqLocal), @SeqLocal) AS SeqLocal,
        @SeqRegional:=IF(size="regional", IF(@SeqLocal + @SeqRegional <= 14, @SeqRegional + 1, @SeqRegional), @SeqRegional) AS SeqRegional,
        @SeqNational:=IF(size="national", IF(@SeqLocal + @SeqRegional + @SeqNational <= 21 , @SeqNational + 1, @SeqNational), @SeqNational) AS SeqNational,
        @SeqInternational:=IF(size="international", IF(@SeqLocal + @SeqRegional + @SeqNational + @SeqInternational <= 28, @SeqInternational + 1, @SeqInternational), @SeqInternational) AS SeqInternational
    FROM
    (
        select *
        from profile 
        where size IN ("local", "regional", "national", "international")
        order by FIELD(size, "local", "regional", "national", "international"), rand() 
    ) Sub1
    CROSS JOIN (SELECT @SeqLocal:=0, @SeqRegional:=0, @SeqNational:=0, @SeqInternational:=0) Sub2
) Sub3
WHERE (size = "local" AND SeqLocal != @SeqLocal)
OR  (size = "regional" AND SeqRegional != @SeqRegional)
OR  (size = "national" AND SeqNational != @SeqNational )
OR  (size = "international" AND SeqInternational != @SeqInternational)

Sqlfiddle在这里： -

http://www.sqlfiddle.com/#!2/cc3b884/14

于 2013-11-08T20:37:49.127 回答