sql-server - 如何获取上午 10 点到现在之间时间戳的行数？

Question

我正在尝试运行一个 T-SQL 查询，该查询将返回包含00:00:00任何给定日期之间的时间戳的所有行。

我使用了以下代码，但这仅返回过去 24 小时内的项目：

SELECT *
FROM table
WHERE timestamp_closed =  DATE(GETDATE()-1);

Answer 1

SELECT *
FROM table
WHERE timestamp_closed BETWEEN CAST(GETDATE() AS DATE) AND GETDATE()

Answer 2

这里有行数：

SELECT COUNT(*)
FROM *yourtable*
WHERE timestamp_closed BETWEEN CAST(GETDATE() AS DATE) AND GETDATE()

Answer 3

您可以为“今天 00:00:00”构建日期值，然后不时执行

WHERE timestamp_closed >= "Today at 00:00:00" and timestamp_closed<=GETDATE()

Answer 4

您可能可以将其包装在一个函数中。

select * 
from table
where datepart(hh,timestamp_closed)*100 + datepart(mi,timestampclosed) < 
    datepart(hh,getdate())*100 + datepart(mi,getdate())

Answer 5

SELECT *
FROM table
WHERE (timestamp_closed >  CAST(@specificDate AS DATE)
AND timestamp_closed <= GETDATE())