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有人可以告诉我为什么当我输入错误的用户名密码时下面的代码不会显示错误。谢谢

公共类 LoginMIDlet 扩展 MIDlet 实现 CommandListener {

private boolean midletPaused = false;
private Display display;

//<editor-fold defaultstate="collapsed" desc=" Generated Fields ">                      
private Form SignIn;
private TextField userName;
private TextField password;
private StringItem sim_Result;
private Form Continue;
private Command _login;
private Command _cancel;
private Command okCommand;
//</editor-fold>                    

/**
 * The LoginMIDlet constructor.
 */
public LoginMIDlet() {
}


 public void validateUser(String user, String Password) {
 if (user.equals("N0203251") && Password.equals("DBTYPX")) {
     switchDisplayable(null, getContinue());
 }

 else {
     switchDisplayable(null, getSignIn());
 Alert error = new Alert("Login Incorrect", "Please try again", null, AlertType.ERROR);
 error.setTimeout(Alert.FOREVER);
 userName.setString("");
 password.setString("");
 display.setCurrent(error);
 }

}

4

1 回答 1

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在“其他”中:

switchDisplayable(null, getSignIn());

也许这条线不允许进程到达“警报”线。

祝你好运!

于 2009-12-31T17:02:27.950 回答