0

这是我的表'dp'

Year      | Month     | Payment|  Payer_ID | Payment_Recipient |
2008/2009 | July      | 100000 |     1     |        John       |
2008/2009 | August    | 200000 |     1     |        Jane       |
2009/2010 | August    | 150000 |     1     |        Jane       |
2009/2010 | September | 175000 |     1     |        John       |

我需要在我的 php 页面中这样的输出：

Year      |       July     |      August   |     September | 
2008/2009 | 100000 | John  | 200000 | Jane |    0   |   -  | 
2009/2010 |    0   |   -   | 150000 | Jane | 175000 | John |

我使用这个 sql 查询：

$query_sql = "SELECT
   year
 , SUM(IF(Month='July', Payment, 0)) As 'July'
 , SUM(IF(Month='August', Payment, 0)) As 'August'
 , SUM(IF(Month='September', Payment, 0)) As 'September'
FROM 
 dp
WHERE 
 Payer_ID = 1
GROUP BY
 Year";


<table>
<tr>
<td>year</td>
<td>July</td>
<td>August</td>
<td>September</td>
</tr>
<?php
while($data=mysql_fetch_array($sql)){
?>
<tr>
<td><?php echo $data['year']; ?></td>
<td><?php echo $data['July']; ?></td>
<td><?php echo $data['August']; ?></td>
<td><?php echo $data['September']; ?></td>
</tr>
<?php } ?>
</table>

并且输出总是这样： 

Year      |  July  | August | September | 
2009/2010 |    0   | 150000 | 175000    |

仅显示 1 年（不循环播放）。

有人可以帮我修复'sum（if'）中的代码以包括付款人并修复我在php中的变量以循环吗？

4

2 回答 2

2

粗略的 SQL 方法：-

   SELECT DISTINCT dp.Year, SubJuly.Payment, SubJuly.Payment_Recipient, SubAugust.Payment, SubAugust.Payment_Recipient, SubSeptember.Payment, SubSeptember.Payment_Recipient
    FROM dp
    LEFT OUTER JOIN
    ( 
        SELECT Year, Month, Payment, Payer_ID, Payment_Recipient 
        FROM dp
        WHERE Month = 'July'
    ) SubJuly
    ON dp.Year = SubJuly.Year
    LEFT OUTER JOIN
    ( 
        SELECT Year, Month, Payment, Payer_ID, Payment_Recipient 
        FROM dp
        WHERE Month = 'August'
    ) SubAugust
    ON dp.Year = SubAugust.Year
    LEFT OUTER JOIN
    ( 
        SELECT Year, Month, Payment, Payer_ID, Payment_Recipient 
        FROM dp
        WHERE Month = 'September'
    ) SubSeptember
    ON dp.Year = SubSeptember.Year
WHERE  dp.Payer_ID = 1

通过使用月/年列表并将其与原始表左连接，然后只处理 php.ini 中的行更改，它可能会更有效地完成。

将其返回到您的原始 php 中：-

<?php


$query_sql = "   SELECT DISTINCT dp.Year, SubJuly.Payment, SubJuly.Payment_Recipient, SubAugust.Payment, SubAugust.Payment_Recipient, SubSeptember.Payment, SubSeptember.Payment_Recipient
    FROM dp
    LEFT OUTER JOIN
    ( 
        SELECT Year, Month, Payment, Payer_ID, Payment_Recipient 
        FROM dp
        WHERE Month = 'July'
    ) SubJuly
    ON dp.Year = SubJuly.Year
    LEFT OUTER JOIN
    ( 
        SELECT Year, Month, Payment, Payer_ID, Payment_Recipient 
        FROM dp
        WHERE Month = 'August'
    ) SubAugust
    ON dp.Year = SubAugust.Year
    LEFT OUTER JOIN
    ( 
        SELECT Year, Month, Payment, Payer_ID, Payment_Recipient 
        FROM dp
        WHERE Month = 'September'
    ) SubSeptember
    ON dp.Year = SubSeptember.Year
WHERE  dp.Payer_ID = 1";

....................
?>
<table>
<tr>
<td>year</td>
<td colspan='2'>July</td>
<td colspan='2'>August</td>
<td colspan='2'>September</td>
</tr>
<?php
while($data=mysql_fetch_assoc($sql))
{
    echo "<tr><td>".implode("</td><td>", $data)."</td></tr>";
} 
?>
</table>

请注意，您可能应该使用 mysqli_* 函数而不是 mysql_* 函数。

于 2013-11-08T12:59:28.920 回答
0

你的代码是正确的..我认为你使用

 mysql_fetch_array

while 循环之前的函数也是。检查你的代码

于 2013-11-08T12:51:55.007 回答