1

在link1和link2的帮助下，我为我的两个列表视图创建了一个 ContextMenu，如下所示

    final int DELETE = 0;
    final int CANCEL = 1;
@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo){
    super.onCreateContextMenu(menu, v, menuInfo);
    switch(v.getId()){
    case R.id.history_listView:
        menu.setHeaderTitle("Delete History?");
        menu.add(0, DELETE, 0, "Delete");
        menu.add(0, CANCEL, 0, "Cancel");
        break;

    case R.id.bookmark_listView:
        menu.setHeaderTitle("Delete Bookmark?");
        menu.add(0, DELETE, 0, "Delete");
        menu.add(0, CANCEL, 0, "Cancel");
    }
}

现在我想要两个 onContextItemSelected 方法，一个用于历史记录，另一个用于书签。我为历史创建了一个，效果很好。

@Override
public boolean onContextItemSelected(MenuItem item){
    AdapterContextMenuInfo info = (AdapterContextMenuInfo) item.getMenuInfo();

    switch(item.getItemId()){
    case DELETE:
        String deleteSelectedHistory = (String) historyData.get(info.position);
        historyData.remove(info.position);
        historyAdapter.notifyDataSetChanged();

        break;

    case CANCEL:
        break;
    }
    return false;
}

但我无法为书签创建另一个。在同一个活动中是否可以有另一个 onContextItemSelected 方法？或者有没有办法创建第二个？

4

1 回答 1

1

请检查此代码。它可能会帮助你。

final int HIS_DELETE = 0;
final int HIS_CANCEL = 1;
final int BM_DELETE = 2;
final int BM_CANCEL = 3;

@Override
public void onCreateContextMenu(ContextMenu menu, View v,
        ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);
    switch (v.getId()) {
    case R.id.history_listView:
        menu.setHeaderTitle("Delete History?");
        menu.add(0, HIS_DELETE, 0, "Delete");
        menu.add(0, HIS_CANCEL, 0, "Cancel");
        break;

    case R.id.bookmark_listView:
        menu.setHeaderTitle("Delete Bookmark?");
        menu.add(0, BM_DELETE, 0, "Delete");
        menu.add(0, BM_CANCEL, 0, "Cancel");
    }
}

和 onContextItemSelected 方法一样，

    @Override
public boolean onContextItemSelected(MenuItem item) {
    AdapterContextMenuInfo info = (AdapterContextMenuInfo) item
            .getMenuInfo();

    switch (item.getItemId()) {
    case HIS_DELETE:
        Log.d("System out", "HIS_DELETE");
        break;
    case HIS_CANCEL:
        Log.d("System out", "HIS_CANCEL");
        break;
    case BM_DELETE:
        Log.d("System out", "BM_DELETE");
        break;
    case BM_CANCEL:
        Log.d("System out", "BM_CANCEL");
        break;
    }
    return false;
}
于 2013-11-08T10:32:05.103 回答