4

我是winforms的新手..我正在尝试将DataGridView的两列设置为仅数字..我不希望用户能够在单元格中输入任何内容，除非它在一列中是自然数而在另一列中是数值（总是一位小数）。我认为这很简单..但即使在从 stackoverflow 和其他网站尝试了很多东西之后，我仍然无法实现这一点。

If DataGridView1.CurrentCell.ColumnIndex = 8 Then

    If Not Char.IsControl(e.KeyChar) AndAlso Not Char.IsDigit(e.KeyChar) AndAlso e.KeyChar <> "."c Then
        e.Handled = True
    End If

End If
4

8 回答 8

12

试试这个代码

 Private Sub DataGridView1_EditingControlShowing(ByVal sender As Object, ByVal e As System.Windows.Forms.DataGridViewEditingControlShowingEventArgs) Handles DataGridView1.EditingControlShowing

        If DataGridView1.CurrentCell.ColumnIndex = 2 Then

            AddHandler CType(e.Control, TextBox).KeyPress, AddressOf TextBox_keyPress

        ElseIf DataGridView1.CurrentCell.ColumnIndex = 1 Then

            AddHandler CType(e.Control, TextBox).KeyPress, AddressOf TextBox_keyPress1


        End If

    End Sub

    Private Sub TextBox_keyPress(ByVal sender As Object, ByVal e As KeyPressEventArgs)

        If Char.IsDigit(CChar(CStr(e.KeyChar))) = False Then e.Handled = True

    End Sub

    Private Sub TextBox_keyPress1(ByVal sender As Object, ByVal e As KeyPressEventArgs)

        If Not (Char.IsDigit(CChar(CStr(e.KeyChar))) Or e.KeyChar = ".") Then e.Handled = True

    End Sub

TextBox_keyPress 事件仅用于数字

TextBox_keyPress1 十进制数值事件

于 2013-11-08T10:06:53.910 回答
1

如果只关心数据类型验证，那么您可以像这样使用 CellValidating 事件

    private void dataGridView1_CellValidating(object sender, DataGridViewCellValidatingEventArgs e)
    {
        //e.FormattedValue  will return current cell value and 
        //e.ColumnIndex & e.RowIndex will rerurn current cell position

        // If you want to validate particular cell data must be numeric then check e.FormattedValue is all numeric 
        // if not then just set  e.Cancel = true and show some message 
        //Like this 

        if (e.ColumnIndex == 1)
        {
            if (!IsNumeric(e.FormattedValue))  // IsNumeric will be your method where you will check for numebrs 
            {
                MessageBox.Show("Enter valid numeric data");
                dataGridView1.CurrentCell.Value = null;
                e.Cancel = true;

            }

        }

    }
于 2013-11-08T10:10:49.537 回答
0 
If e.ColumnIndex = 6 Then
    If Not IsNumeric(e.FormattedValue) Then
        ' IsNumeric will be your method where you will check for numebrs 
        MessageBox.Show("Enter valid numeric data")
        DataGridView1.CurrentCell.Value = Nothing

        e.Cancel = True

    End If
End If
于 2015-03-12T12:47:12.227 回答
0

以下代码是 Satish 解决方案的扩展。它将有助于控制 DataGridView 单元格的值。文本框函数仅用于将单元格附加到文本框事件。无需在 DataGridView 或表单上的任何位置添加文本框。

Private Sub DataGridView_EditingControlShowing(ByVal sender As Object, ByVal e As System.Windows.Forms.DataGridViewEditingControlShowingEventArgs) Handles DataGridView.EditingControlShowing
    If DataGridView.CurrentCell.ColumnIndex = 2 Then 'Numeric column with decimal point
        AddHandler CType(e.Control, TextBox).KeyPress, AddressOf TextBox_keyPress

    ElseIf DataGridView.CurrentCell.ColumnIndex = 3 Then 'Numeric column without Decimal
        AddHandler CType(e.Control, TextBox).KeyPress, AddressOf TextBox_keyPress1

    ElseIf DataGridView.CurrentCell.ColumnIndex = 4 Then 'Selected Values only
        AddHandler CType(e.Control, TextBox).KeyPress, AddressOf TextBox_keyPress2

    ElseIf DataGridView.CurrentCell.ColumnIndex = 5 Then 'Email Column
        AddHandler CType(e.Control, TextBox).KeyPress, AddressOf TextBox_keyPress3

    End If

End Sub

Private Sub TextBox_keyPress(ByVal sender As Object, ByVal e As KeyPressEventArgs)
    'Allows Numeric values, one decimal point and BackSpace key
    Dim numbers As Windows.Forms.TextBox = sender
    If InStr("1234567890.", e.KeyChar) = 0 And Asc(e.KeyChar) <> 8 Or (e.KeyChar = "." And InStr(numbers.Text, ".") > 0) Then
        e.KeyChar = Chr(0)
        e.Handled = True
    End If
End Sub

Private Sub TextBox_keyPress1(ByVal sender As Object, ByVal e As KeyPressEventArgs)
    'Allow Numeric values, BackSpace key. Disallows decimal point (i.e. dot) 
    Dim numbers As Windows.Forms.TextBox = sender
    If InStr("1234567890", e.KeyChar) = 0 And Asc(e.KeyChar) <> 8 Then
        e.KeyChar = Chr(0)
        e.Handled = True
    End If
End Sub


Private Sub TextBox_keyPress2(ByVal sender As Object, ByVal e As KeyPressEventArgs)
    'Allow selected values only
    If InStr("1234567890!@#$%^&*()_+=-", e.KeyChar) > 0 Then
        e.KeyChar = Chr(0)
        e.Handled = True
    End If
End Sub

Private Sub TextBox_keyPress3(ByVal sender As Object, ByVal e As KeyPressEventArgs)
    'Martch function, Needs to add "Imports System.Text.RegularExpressions" at the top of Class
    'Allows Email values
    Dim Email As Windows.Forms.TextBox = sender
    If Email.Text <> "" Then
        Dim rex As Match = Regex.Match(Trim(Email.Text), "^([0-9a-zA-Z]([-.\w]*[0-9a-zA-Z])*@([0-9a-zA-Z][-\w]*[0-9a-zA-Z]\.)+[a-zA-Z]{2,3})$", RegexOptions.IgnoreCase)
        If rex.Success = False Then
            MessageBox.Show("Please Enter a valid Email Address", "Information", MessageBoxButtons.OK, MessageBoxIcon.Information)
            Email.BackColor = Color.Red
            Email.Focus()
            Exit Sub
        Else
            Email.BackColor = Color.White
        End If
    End If
End Sub
于 2017-09-13T13:45:09.120 回答
0

试试这个代码。它与投票最多的答案几乎相同，但我编辑了KeypressEvent代码以使其变得简单，即使您必须输入十进制数字，您也可以使用它。享受。:)

Private Sub DataGridView1_EditingControlShowing(ByVal sender As Object, ByVal e As System.Windows.Forms.DataGridViewEditingControlShowingEventArgs) Handles DataGridView1.EditingControlShowing

    If DataGridView1.CurrentCell.ColumnIndex = 2 Then

        AddHandler CType(e.Control, TextBox).KeyPress, AddressOf TextBox_keyPress

    End If

End Sub

Private Sub TextBox_keyPress(ByVal sender As Object, ByVal e As KeyPressEventArgs)

     If (Not Char.IsControl(e.KeyChar) _
                AndAlso (Not Char.IsDigit(e.KeyChar) _
                AndAlso (e.KeyChar <> Microsoft.VisualBasic.ChrW(46)))) Then
        e.Handled = True
    End If

End Sub
于 2018-01-10T13:53:47.813 回答
0 
Private Sub DGV_EditingControlShowing(sender As Object, e As System.Windows.Forms.DataGridViewEditingControlShowingEventArgs) Handles DGV_TimeSheetMain.EditingControlShowing
    '       '*************Allow only Numbers in DataGridView*************
    Dim txtEdit As TextBox = e.Control
    'remove any existing handler
    RemoveHandler txtEdit.KeyPress, AddressOf TextEdit_Keypress
    AddHandler txtEdit.KeyPress, AddressOf TextEdit_Keypress
End Sub

Private Sub TextEdit_Keypress(ByVal sender As Object, ByVal e As System.Windows.Forms.KeyPressEventArgs)
    'Test for numeric value or backspace in first column
    If DGV.CurrentCell.ColumnIndex = 1 Then
        If IsNumeric(e.KeyChar.ToString()) Or e.KeyChar = ChrW(Keys.Back) Then
            e.Handled = False 'if numeric display
        Else
            e.Handled = True  'if non numeric don't display
        End If
    End If
End Sub
于 2018-03-05T11:34:27.787 回答
0

用 lambda 试试这个

Private Sub dgv_pararelhp_EditingControlShowing(ByVal sender As Object, ByVal e As System.Windows.Forms.DataGridViewEditingControlShowingEventArgs) Handles dgv_pararelhp.EditingControlShowing
    If dgv_pararelhp.CurrentCell.ColumnIndex = 0 Then'// change this optional your index column.
         AddHandler CType(e.Control, TextBox).KeyPress, Sub(s_, e_)
                                                            If Char.IsDigit(CChar(CStr(e_.KeyChar))) = False Then e_.Handled = True
                                                         End Sub
       End If
End Sub
于 2020-07-09T15:08:47.023 回答
-1 
Private Sub DataGridView1_EditingControlShowing(ByVal sender As Object, ByVal e As         System.Windows.Forms.DataGridViewEditingControlShowingEventArgs) Handles DataGridView1.EditingControlShowing
        AddHandler CType(e.Control, TextBox).KeyPress, AddressOf TextBox_keyPress
 End Sub
 Private Sub TextBox_keyPress(ByVal sender As Object, ByVal e As KeyPressEventArgs)
        If Char.IsDigit(CChar(CStr(e.KeyChar))) = False Then e.Handled = True
        If Not (Char.IsDigit(CChar(CStr(e.KeyChar))) Or e.KeyChar = ".") Then e.Handled = True
        If e.KeyChar = " "c Then e.Handled = False
  End Sub
于 2015-07-28T07:22:11.667 回答