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这是我在Andorid中基于corodova 2.9.0的应用程序中使用的代码。当我尝试上传照片时。应用程序崩溃了。

function uploadPhoto(imageURI)
{
 Ext.Viewport.mask({ xtype: 'loadmask' });               
 var milliseconds = js_yyyy_mm_dd_hh_mm_ss();
 var options = new FileUploadOptions();
 options.fileKey="file";
 options.chunkedMode=false;         options.fileName=App.gvars.userid+milliseconds+imageURI.substr(imageURI.lastIndexOf('/')+1);
 renamedfile=options.fileName;
 options.mimeType="image/jpeg";
 var params = new Object();
 options.params = params;
 var ft = new FileTransfer();
 var url = "http://wish.brammies.com/itemimage/upload.php/";
 ft.upload(imageURI, url, win, fail, options,true);
 }
 function win(r)
 {
  console.log("Code = " + r.responseCode);
  console.log("Response = " + r.response);
  console.log("Sent = " + r.bytesSent);
 }
 function fail(error)
  {
   console.log("An error has occurred: Code = " + error.code);
   console.log("upload error source " + error.source);
   console.log("upload error target " + error.target);
 }

编辑 PHP 代码

<?php 
$folder = “/itemimage/”;
if (is_uploaded_file($_FILES['file']['tmp_name']))  {  
if (move_uploaded_file($_FILES['file']['tmp_name'], $folder.$_FILES['file']['name'])) {
     echo "File uploaded";
} else {
     echo "File not moved to destination folder. Check permissions";
};
} else {
 echo "File is not uploaded.";
};
//you get the following information for each file:
echo $_FILES['file']['name']."</br>"; //represents the name of file uploaded
echo $_FILES['file']['size']."</br>";   //represents the size of file uploaded
echo $_FILES['file']['type']."</br>"; //represents the mime type of file uploaded
echo $_FILES['file']['tmp_name']."</br>";
echo "fdggdr";
?>

安卓运行版本4.1.4

请帮我解决问题。

4

1 回答 1

1

设置 options.chunkedMode=true;

当分块模式为 false 时，Android 上的 HTTP 代码会在发送前尝试在内存中缓冲整个传输。在您的情况下，较大的传输为 15 mb，但对于其他手机，它会更少，因为它们的内存更少，这将导致抛出 OutOfMemory 异常。由于永远不应捕获 OOME，因此应用程序将崩溃。

于 2013-11-08T07:24:02.967 回答