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I am trying to execute this code on Python. This code refers to a LDA, from sklearn.

import numpy as np
from sklearn.lda import LDA

X = np.array ([0.000000, 0.000000, 0.000000, 0.000000, 0.001550, 
               0.000000, 0.000000, 0.000000, 0.000000, 0.000000, 
               0.000000, 0.000000, 0.201550, 0.011111, 0.077778,
               0.011111, 0.000000, 0.000000, 0.000000, 0.000000,
               0.000000, 0.092732, 0.000000, 0.000000, 0.000000,
               0.000000, 0.035659, 0.000000, 0.000000, 0.000000,
               0.000000, 0.066667, 0.000000, 0.000000, 0.010853,
               0.000000, 0.033333, 0.055556, 0.055556, 0.077778, 
               0.000000, 0.000000, 0.000000, 0.268170, 0.000000, 
               0.000000, 0.000000, 0.000000, 0.130233, 0.000000, 
               0.000000, 0.000000, 0.000000, 0.000000, 0.000000,
               0.000000, 0.034109, 0.077778, 0.055556, 0.011111, 
               0.000000, 0.000000, 0.000000, 0.000000, 0.000000,
               0.155388, 0.000000, 0.000000, 0.000000, 0.000000,
               0.181395, 0.000000, 0.000000, 0.000000, 0.000000,
               0.001550, 0.007752, 0.000000, 0.000000, 0.000000, 
               0.000000, 0.000000, 0.011111, 0.088889, 0.033333,
               0.000000, 0.000000, 0.142857, 0.000000, 0.000000,
               0.000000, 0.000000, 0.093023, 0.000000, 0.000000,
               0.000000, 0.000000, 0.000000, 0.009302, 0.010853, 
               0.000000, 0.100000, 0.000000, 0.000000, 0.000000,
               0.000000, 0.022222, 0.088889, 0.033333, 0.238095,
               0.000000, 0.000000, 0.000000, 0.000000, 0.032558,
               0.000000, 0.000000, 0.000000, 0.000000, 0.000000,
               0.182946, 0.000000, 0.000000, 0.000000, 0.000000,
               0.000000, 0.000000, 0.022222, 0.077778, 0.055556,
               0.000000, 0.102757])

y = np.array ([0.000000, 0.000000, 0.008821, 0.000000, 0.000000, 
               0.000000, 0.000000, 0.000000, 0.000000, 0.000000,
               0.000000, 0.000000, 0.179631, 0.010471, 0.036649,
               0.026178, 0.000000, 0.000000, 0.020942, 0.010471,
               0.000000, 0.109215, 0.000000, 0.000000, 0.060144, 
               0.000000, 0.042502, 0.000000, 0.005613, 0.000000,
               0.000000, 0.018444, 0.000000, 0.000000, 0.013633,
               0.020942, 0.031414, 0.083770, 0.015707, 0.041885,
               0.041885, 0.057592, 0.010471, 0.233788, 0.000000,
               0.000000, 0.018444, 0.000000, 0.000000, 0.000000,
               0.000000, 0.000000, 0.090617, 0.000000, 0.000000,
               0.000000, 0.104250, 0.005236, 0.020942, 0.031414,
               0.000000, 0.000000, 0.010471, 0.015707, 0.005236,
               0.056314, 0.000000, 0.000000, 0.026464, 0.000000,
               0.004010, 0.000000, 0.031275, 0.007217, 0.036889,
               0.007217, 0.013633, 0.000000, 0.000000, 0.005236,
               0.047120, 0.057592, 0.015707, 0.010471, 0.047120,
               0.062827, 0.005236, 0.262799, 0.000000, 0.000000,
               0.000000, 0.000000, 0.000802, 0.000000, 0.000000,
               0.000000, 0.001604, 0.000000, 0.052927, 0.000000,
               0.039294, 0.026178, 0.041885, 0.031414, 0.000000,
               0.000000, 0.041885, 0.073298, 0.000000, 0.308874,
               0.000000, 0.000000, 0.000000, 0.000000, 0.000000,
               0.000000, 0.000000, 0.000000, 0.000000, 0.000000,
               0.236568, 0.000000, 0.000000, 0.000000, 0.000000,
               0.000000, 0.000000, 0.000000, 0.020942, 0.015707,
               0.000000, 0.029010])

clf = LDA() clf.fit(X,y) print(clf.predict([0, 2]))

And show me this error message:

clf.fit(X, y)
n_samples, n_features = X.shape
ValueError: need more than 1 value to unpack

What I do to fix it? I could not find this solution on documentation.

4

1 回答 1

1

你的数组是一维的。当你这样做时：

n_samples, n_features = X.shape

X.shape 不是样本和特征的矩阵，而是形状 (106,) 的数组。您需要多个样品。照原样，您有一堆功能和一个样本。具有 4 个特征的 4 个样本的矩阵将被定义为：

featureMat = np.array([[ 10, 30, 40, 50],
                       [ 5,  6,  7,  8],
                       [ 54, 75, 6,  56],
                       [ 65, 34, 23, 22]])

所以 featureMat.shape 将是 (4,4)。

于 2013-11-07T23:47:09.047 回答