0

我想写入位于我服务器上的数据库。Select-Statements 工作得很好，但我想在表中创建一个新条目。我为此使用 INSERT 并这样做：

Java 代码（应用程序/客户端）：

        //the year data to send
    ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
    nameValuePairs.add(new BasicNameValuePair("id", idNumber.getText().toString()));
    nameValuePairs.add(new BasicNameValuePair("name", nameText.getText().toString()));

    //http post
    try{
            HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost("http://olli130.myds.me/sqlcreate.php");
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();
            is = entity.getContent();

            Log.i("Sent to Server", "name: " + nameText.getText().toString() + ", id: " + idNumber.getText().toString());
    }catch(Exception e){
            Log.e("log_tag", "Error in http connection "+e.toString());
    }

}

和 PHP 代码：

<?php
include 'sqlcon.php';

    $connection=mysql_connect($mysqlhost, $mysqluser, $mysqlpwd) or die
    ("Verbindungsversuch fehlgeschlagen");

    mysql_select_db($mysqldb, $connection) or die("Konnte die Datenbank nicht
    waehlen.");

     $sql = "INSERT INTO Testtable (id, descr)
     VALUES (".$_REQUEST['id']", '".$_REQUEST['name']"')";

     mysql_query($sql) or die (mysql_error());
     mysql_close($connection);
    ?>

我做错了什么吗？为什么它不起作用？

4

0 回答 0