objective-c - caseInsensitiveCompare: 与 isCaseSensitiveLike: 之间的不一致：

Question

我想知道是否有人可以解释这种看似奇怪的行为？

NSString *emptyString = @"";
NSString *aBunchOfAsterisks = @"*********";

NSLog(@"NSString's caseInsensitiveCompare: says the two strings are %@", [emptyString caseInsensitiveCompare:aBunchOfAsterisks] == NSOrderedSame ? @"EQUAL" : @"NOT EQUAL");
NSLog(@"NSComparisonMethods protocol's isCaseInsensitiveLike: says aBunchOfAsterisks is %@ to emptyString", [emptyString isCaseInsensitiveLike:aBunchOfAsterisks] ? @"EQUAL" : @"NOT EQUAL");
NSLog(@"NSComparisonMethods protocol's isCaseInsensitiveLike: says emptyString is %@ to aBunchOfAsterisks", [aBunchOfAsterisks isCaseInsensitiveLike:emptyString]? @"EQUAL" : @"NOT EQUAL");

记录以下内容

NSString的caseInsensitiveCompare：说这两个字符串不
相等

为什么是第二种比较方法，即

[emptyString isCaseInsensitiveLike:aBunchOfAsterisks];

返回是？更糟糕的是，这似乎只有在字符是“ * ”时才会发生。aBunchOfAsterisks中的任何其他值以及所有 3 种比较方式，都返回NO。

Answer 1

从标题：

// argument should be a string using simple shell wildcards (* and ?).
// (e.g. "Stev*" or "N?XT").
// Returns NO if receiver is not an NSString.

因此你的*********字符串减少到*，因此它匹配空字符串......