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user-a向 发送订阅请求user-b。订阅模式已设置为accept_all。此外，已经为两个用户注册了数据包侦听器。

当向此方法user-a发送请求时user-b被调用：

    private void searchUser(java.awt.event.ActionEvent evt) {                            
        try {
            String userToSearch = jTextField1.getText(); 
                if(!xmppParamInit) {
                    initUXmppP();
                    xmppParamInit = true;
                }
                Presence subscribe = new Presence(Presence.Type.subscribe);
                userToSearch += "@localhost";
                subscribe.setTo(userToSearch);
                ofConnection.sendPacket(subscribe); // Send the 'subscribe' packet
        }catch(Exception exc) {
            exc.printStackTrace();
        }
    }

在此方法之前，调用以下方法：

private void startPLThread() { // start packet-listener-thread
    Runnable r = new Runnable() {
        @Override
        public void run() {
            startPL();
        }
    };
    new Thread(r,"packet listener thread").start();
}

private void startPL() {
    PacketListener pListener = new PacketListener() {
        @Override
        public void processPacket(Packet packet) {System.out.println("Inside process packet");
            if(packet instanceof Presence) {
                Presence presence = (Presence) packet;
                Presence subscription = new Presence(Presence.Type.subscribe);
                subscription.setTo(presence.getFrom());
                System.out.println("presence.getFrom : " + presence.getFrom());
                ofConnection.sendPacket(subscription);
            }
        }
    };

    PacketFilter pFilter = new PacketFilter() {
        @Override
        public boolean accept(Packet packet) {
            return true;
        }
    };

    ofConnection.addPacketListener(pListener, pFilter);
}

问题是user-a可以在他的花名册中看到user-b，但在其花名册user-b中看不到user-a。我不明白这是为什么。可能是什么问题呢 ？

accept_all在从搜索用户中调用的此方法中已将订阅模式设置为：

private void initUXmppP() { // Initialize user-xmpp-parameters
    Roster roster = ofConnection.getRoster();
    roster.setSubscriptionMode(Roster.SubscriptionMode.accept_all);
}

这是一个 GUI 应用程序，我尝试让两个用户都在线

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