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我解析一个 XML 文件，解析后得到一个 NSDictionary 对象（命名为 XMLDictionary）。我正在解析这个：

<result><node><id>27</id><name>Name 1</name><type>0</type><price>0</price><img>/upload/iblock/1a1/1a138b2d4da6e42398beeb21acc8e84f.png</img></node><node><id>28</id><name>Name 2</name><type>0</type><price>0</price><img>/upload/iblock/b72/b724d1550f93987a73b04974b5f7390e.png</img></node></result>

之后我正在尝试这个（titleArr - NSArray）：

_titleArr = [[[[_xmlDictionary objectForKey:@"result"] objectForKey:@"node"] objectForKey:@"name"] valueForKey:@"text"];

在运行时，我在上面的行中收到此错误：“线程 1：信号 SIGABRT”。我该如何解决这个问题？

4

2 回答 2

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NSError* parseError = nil;
_xmlDictionary = [XMLReader dictionaryForXMLString:myXMLString error:&parseError];
if (parseError != nil) {
    NSLog(@"Error on XML parse: %@", parseError);
}

NSLog(@"The full dictionary is %@", _xmlDictionary);

NSDictionary* result = [_xmlDictionary objectForKey:@"result"];
NSLog(@"'result' = %@", result);
NSDictionary* node = [result objectForKey:@"node"];
NSLog(@"'node' = %@", node);
NSString* name = [node objectForKey:@"name"];
NSLog(@"'name' = %@", name);

至少，如果失败，错误将被隔离到单个操作中。NSLogs 会在每一步之后向您显示值。

于 2013-11-07T16:13:03.480 回答
0

尝试这个：

NSArray *arrResult = [_xmlDictionary objectForKey:@"result"];
for(int i = 0; i < [arrResult count]; i++)
{
    NSArray *arrNode = [arrResult objectAtIndex:i] valueForKey:@"node"];
    NSString *sName = [arrNode valueForKey:@"Name"];
    NSLog(@"Name : %@",sName);
}

编辑后的答案

  NSArray *arrResult = [_xmlDictionary valueForKey:@"result"];
    for (int i = 0; i < [arrResult count]; i++) {
        NSDictionary *dicNode = [[arrResult objectAtIndex:i] valueForKey:@"Node"];
        NSString *sName = [dicNode valueForKey:@"Name"];
        NSLog(@"Name : %@",sName);
    }
于 2013-11-07T12:05:36.740 回答