0

我有 A、B、C 类：

 public class A 
{
    public int Prop1;
    public int Prop2;
    public int Prop3;
    public int Prop4;
    public int Prop5;
}

public class B:A
{
  public int PropB1;
  public int PropB2;
}

public class C:A
{
   public int PropC1;
}

我从可用变量创建对象 B、C：

var b = new B
{
 Prop1 = param1,
 Prop2 = param2,
 Prop3 = param3,
 Prop4 = param4,
 Prop5 = param5,
 PropB1 = param6,
 PropB2 = param7,
}
var c = new C
{
 Prop1 = param1,
 Prop2 = param2,
 Prop3 = param3,
 Prop4 = param4,
 Prop5 = param5,
 PropC1 = param8
}

使用这种编码风格，它有重复的代码。如何避免这种情况。请帮我。谢谢。

 Prop1 = param1,
 Prop2 = param2,
 Prop3 = param3,
 Prop4 = param4,
 Prop5 = param5,

谢谢。

4

3 回答 3

2

将构造函数添加到您的类。这可以节省您在创建实例时键入属性名的时间。

像这样：

public class A  {
    public A(int prop1, int prop2, int prop3, int prop4, int prop5) {
        Prop1 = prop1;
        Prop2 = prop2;
        Prop3 = prop3;
        Prop4 = prop4;
        Prop5 = prop5
    }
    public int Prop1;
    public int Prop2;
    public int Prop3;
    public int Prop4;
    public int Prop5;
}

public class B : A {
    public B(int prop1, int prop2, int prop3, int prop4, int prop5, int propB1, int propB2) :
        base(prop1, prop2, prop3, prop4, prop5) {
        PropB1 = propB1;
        PropB2 = propB2
    }
    public int PropB1;
    public int PropB2;
}

public class C : A {
    public C(int prop1, int prop2, int prop3, int prop4, int prop5, int propC1) :
        base(prop1, prop2, prop3, prop4, prop5) {
        PropC1 = propC1;
    }
    public int PropC1;
}

var b = new B(param1, param2, param3, param4, param5, param6, param7);
var c = new C(param1, param2, param3, param4, param5, param8);
于 2013-11-07T10:44:20.470 回答
1

那这个呢 ：

public class A 
{
    public int Prop1;
    public int Prop2;
    public int Prop3;
    public int Prop4;
    public int Prop5;

    public A()
    {
    }

    public A(A a)
    {
        this.Prop1 = a.Prop1;
        this.Prop2 = a.Prop2;
        this.Prop3 = a.Prop3;
        this.Prop4 = a.Prop4;
        this.Prop5 = a.Prop5;
    }
}

public class B:A
{
    public int PropB1;
    public int PropB2;

    public B(A a) : base(a)
    {
    }
}

public class C:A
{
    public int PropC1;

    public C(A a) : base(a)
    {
    }
}

然后，您可以像这样创建对象：

var a = new A
{
 Prop1 = param1,
 Prop2 = param2,
 Prop3 = param3,
 Prop4 = param4,
 Prop5 = param5
};

var b = new B(a)
{     
 PropB1 = param6,
 PropB2 = param7
}

var c = new C(a)
{
 PropC1 = param8
}
于 2013-11-07T10:50:04.767 回答
0

您可以将参数包装到另一个对象中。

class AArg {
  public int prop1;
  public int prop2;
  public int prop3;
  public int prop4;
  public int prop5;
}

class A {
  public A(AArg args) {
     // COPY(!) the values.
     prop1 = args.prop1;
     prop2 = args.prop2;
     prop3 = args.prop3;
     prop4 = args.prop4;
     prop5 = args.prop5;
     prop6 = args.prop6;
  }
}

class B extends A {
  public int probB1;
  public B(Aargs aArgs, int probB1) {
    super(aArgs);
    this.probB1 = probB1;
  }
}

当您使用此模式时，重要的是复制参数包装器的内容，而不是将其保存为字段。如果您不复制它，如果您的对象的创建者重用参数，则对一个对象的更改可能会影响另一个对象：

AArg arg = new AArg(1,2,3,4,5);
A a1 = new A(arg);
arg.prob1 = 10;
A a2 = new A(arg);
a2.prob2 = 20
// Now a1.prob1 == 10 and a1.prob2 == 20

您还可以使参数对象不可变，这样可以安全地存储它，但这也会使您的 A/B/C 对象（部分）不可变。

于 2013-11-07T11:15:12.263 回答