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我正在尝试生成代理。我从示例文件夹中复制了一个示例 xml 并对其进行了修改。

操作系统：Windows 8.1

Java 版本：1.7.0_45（32 或 64 位）

JNI4NET 版本：0.8.6

命令行：proxygen config.xml

配置.xml：

<?xml version="1.0" encoding="utf-8" ?>
<jni4net-proxygen xmlns="http://jni4net.sf.net/0.8.7.0/toolConfig.xsd">
  <!-- Location where .java files will be generated into. It's relative or absolute path. -->
  <TargetDirJvm>java</TargetDirJvm>
  <!-- Location where .cs files will be generated into. It's relative or absolute path. -->
  <TargetDirClr>csharp</TargetDirClr>

  <!-- List of class paths (.jar files or directories) which define known classes for generator-->
  <ClassPath Path="scr-classicconnector-7.5.1.jar"/>

  <!-- List of Java classes which should have proxy generated -->
  <JavaClass TypeName="com.saperion.connector.SaClassicConnector"/>

</jni4net-proxygen>

我得到的错误：

jni4net.proxygen - Copyright (C) 2009 Pavel Savara - licensed under GPLv3

System.InvalidOperationException: There is an error in XML document (20, 2). ---> System.InvalidOperationException: <jni4net-proxygen xmlns='http://jni4net.sf.net/0.8.7.0/toolConfig.xsd'> was not expected.
   at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReaderToolConfig.Read8_jni4netproxygen()
   --- End of inner exception stack trace ---
   at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle, XmlDeserializationEvents events)
   at System.Xml.Serialization.XmlSerializer.Deserialize(Stream stream)
   at net.sf.jni4net.proxygen.Program.Work(String[] args)
   at net.sf.jni4net.proxygen.Program.Main(String[] args)

可以请人帮忙吗...

谢谢， 安德烈亚斯

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1 回答 1

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谢谢 Pavel Savara：问题是用于 proxygen 0.8.7 版的 xmlns。我将它与该工具的 0.8.6 版本一起使用。将其更改为“0.8.6.0”后，它起作用了。

于 2013-11-08T08:08:43.190 回答