python - Python程序不断将辅音移动到字符串的末尾，直到第一个字母是元音

Question

例如，如果我输入bob，它应该给我obb. 同样，类似的东西plank应该给我ankpl。

s = input("What word do you want translated?")
first = s[0]
vowel = "aeiou"
for i in range (1, len(s)):
     if first in vowel:
        s = s + "way"
        print (s)
else:
        s = s[1:] + s[0]
        print (s)

这目前只给我lankpfor plank. 谢谢！

Answer 1

它实际上可以变得更简单：

s = raw_input("What word do you want translated?").strip()
vowel = set("aeiou")
if vowel & set(s):
    while s[0] not in vowel:
        s = s[1:] + s[0]
    print s
else:
    print "Input has no vowels"

Answer 2

您只设置first = s[0]一次，并且在循环之前完成。您可能希望将其设置在 for 循环中。

Answer 3

您的程序的问题else是 没有缩进到正确的级别，因此您有一个for/else构造而不是if/else.

这是一种更有效的方法。

如果vowels = set("aeiou")，你可以像这样得到第一个元音的位置

next(i for i, j in enumerate(s) if j in vowels)

例如：

>>> s = "plank"
>>> vowels = set("aeiou")
>>> next(i for i, j in enumerate(s) if j in vowels)
2

和

>>> s[2:] + s[:2]
'ankpl'

所以现在你只需要操作字符串一次。

如果没有元音，代码会引发异常而不是永远运行:)

>>> s="why why why?"
>>> next(i for i, j in enumerate(s) if j in vowels)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
StopIteration

Answer 4

搜索元音然后将字符串旋转一次可能更有效一些：

vowels = 'aeiou'

for index, character in enumerate(s):
    if character in vowels: break

s = s[index:] + s[:index]

Answer 5

这将起作用

#Move Consonants to the End
def MoveConsonants(input1):
    contains_vowel = False
    for letter in input1: #Check if the work contains a vowel or not
        if letter in 'aeiou':
            contains_vowel = True
    #If the word doesn't contain a vowel, return the same word
    if not contains_vowel: 
        return input1

    #Check if the first letter is a vowel, if so, we can return the string
    if input1[0] in 'aeiou':
        return input1

    #if the first letter is not a vowel, move the first letter to the end and repeat the process
    input1 = input1[1:] + input1[0]
    return MoveConsonants(input1)
print(MoveConsonants('Plank'))