0

I am trying to find out how can i have the same result in php and C#. I have this code in c#:

string date_server = "201311060930|aabbcc@test.com|test";
SHA1 sha_1 = new SHA1CryptoServiceProvider();
byte[] array = Encoding.ASCII.GetBytes(date_server);
array = sha_1.ComputeHash(array);

And the result is: 2201676219018622422190124192121212501517223823286232147

So i want obtain the same result in PHP:

Code:

$finalString = "201311060930|aabbcc@test.com|test";
$a = utf8_encode($finalString);
$b = unpack('C*', $a); 
$string = implode($b);
$sHash = sha1($string);

But i can't obtain the same result: 3f24039aeb68e306f93161a9e9df2c44e7e1ce15

Thanks

4

1 回答 1

1

只需运行您的 c# 代码,结果应该是

array = {68,176,83,152,44,38,107,201,112,139,17,80,242,94,158,181,136,198,98,193}

我不知道2201676219018622422190124192121212501517223823286232147从哪里来

如果第二个参数为真, sha1将返回原始结果,您可以通过以下方式将其转换为arraybyte[]在 C# 中)unpack

$finalString = "201311060930|aabbcc@test.com|test";
$sHash = sha1($finalString, true);
echo join(',',unpack('C*', $sHash));

并且输出与 C# 相同

68,176,83,152,44,38,107,201,112,139,17,80,242,94,158,181,136,198,98,193
于 2013-11-06T16:44:29.423 回答