php - PHP日期：如何检查当年是否没有过去的月份？

Question

如何检查当前年份（例如 2013 年）是否不再有过去的月份（如一月、二月...十月），然后做点什么？

我有这些代码行，

# Set month array for the calendar.
$months_calender = array();

# Set current month and curren year.
$current_month = (int)date('m');
$current_year = (int)date('Y');

for($x = $current_month; $x < $current_month+12; $x++) $months_calender[] = date('M', mktime(0, 0, 0, $x, 1));

获取下面的月份列表，

Array (
    [0] => Nov
    [1] => Dec
    [2] => Jan
    [3] => Feb
    [4] => Mar
    [5] => Apr
    [6] => May
    [7] => Jun
    [8] => Jul
    [9] => Aug
    [10] => Sep
    [11] => Oct )

然后我想打印月份所属的年份，

foreach($months_calender as $index => $month_calender)
{
    if current year has no more Jan then print next year, for instance 2014
}

有任何想法吗？

Answer 1

你可以在 for 语句中得到 year

for($x = $current_month; $x < $current_month+12; $x++) {
    $months_calender[] = date('M', mktime(0, 0, 0, $x, 1));
    $years[] = date('Y', mktime(0, 0, 0, $x, 1));
}

Answer 2

# Set month array for the calendar.
$months_calender = array();
$current_month = (int)date('m');

for($x = $current_month; $x < $current_month+12; $x++) {
    $time = mktime(0, 0, 0, $x, 1);
    $months_calender[] = array(date('M', $time), date('Y', $time));
}

foreach($months_calender as $monthYear) {
   list($month, $year) = $monthYear;
   echo "$month, $year\n";
}