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这是我的 [资源表] 我正在获取我的数据：

Start Date                 Time From  Time To  Time From To    Training Room
2011-05-24 00:00:00.000    8:00       23:00    8:00 - 23:00    Room1
2011-05-25 00:00:00.000    1:00       23:00    1:00 - 23:00    Room1
2011-05-26 00:00:00.000    1:00       23:00    1:00 - 23:00    Room1
2011-05-04 00:00:00.000    20:00      23:00   20:00 - 23:00    Room2
2011-05-05 00:00:00.000    20:00      22:00   20:00 - 22:00    Room2
2011-05-20 00:00:00.000    20:00      23:00   20:00 - 23:00    Room3
2011-05-21 00:00:00.000    17:00      19:00   17:00 - 19:00    Room2

我想要的是填充这张表[FACT Training]：

在此处输入图像描述

但是我在填充没有空值的表时遇到问题。由于我想向每一天的列插入数据，因此只插入特定的星期几名称：

WHERE datename(dw,[Start Date]) = 'Monday'
WHERE datename(dw,[Start Date]) = 'Tuesday'
etc...

所以我的插入看起来像这样：

在此处输入图像描述

但是需要每天过滤...

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1 回答 1

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查看您描述的问题，我开始时仅将列值放入正确的星期几，这将创建 7 行，每行仅填充[Start Date]下降日的列。

SELECT
    [Monday] =
        CASE WHEN DATENAME(DW,[Start Date]) = 'Monday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END
    ,[Tuesday] = 
        CASE WHEN DATENAME(DW,[Start Date]) = 'Tuesday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END
    ,[Wednesday] = 
        CASE WHEN DATENAME(DW,[Start Date]) = 'Wednesday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END
    ,[Thursday] = 
        CASE WHEN DATENAME(DW,[Start Date]) = 'Thursday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END
    ,[Friday] = 
        CASE WHEN DATENAME(DW,[Start Date]) = 'Friday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END
    ,[Saturday] = 
        CASE WHEN DATENAME(DW,[Start Date]) = 'Saturday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END
    ,[Sunday] = 
        CASE WHEN DATENAME(DW,[Start Date]) = 'Sunday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END
FROM
    [Resource table]

但后来我想，您可能希望在一行中显示所有这些，在这种情况下，您需要按某个值或多个值对它们进行分组。我不知道用于为组创建列值串联列表的 SQL 聚合函数，因此您可能需要创建一个，但您可以按培训室分组，并且如果每次培训每天只有一个条目room 可以使用类似下面的东西（SQL 纯粹主义者现在可能想把目光移开）：

SELECT
    [Week Id] = CONVERT(VARCHAR,DATEPART(YEAR,[Start Date])) + '-' + CONVERT(VARCHAR,DATEPART(WEEK,[Start Date]))
    ,[Training Room]
    ,[Monday] = MAX(CASE WHEN DATENAME(DW,[Start Date]) = 'Monday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END)
    ,[Tuesday] = MAX(CASE WHEN DATENAME(DW,[Start Date]) = 'Tuesday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END)
    ,[Wednesday] = MAX(CASE WHEN DATENAME(DW,[Start Date]) = 'Wednesday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END)
    ,[Thursday] = MAX(CASE WHEN DATENAME(DW,[Start Date]) = 'Thursday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END)
    ,[Friday] = MAX(CASE WHEN DATENAME(DW,[Start Date]) = 'Friday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END)
    ,[Saturday] = MAX(CASE WHEN DATENAME(DW,[Start Date]) = 'Saturday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END)
    ,[Sunday] = MAX(CASE WHEN DATENAME(DW,[Start Date]) = 'Sunday' THEN ISNULL([Training Room],'') + N' - ' + [Time From To] ELSE '' END)
FROM
    [Resource table] 
GROUP BY 
    CONVERT(VARCHAR,DATEPART(YEAR,[Start Date])) + '-' + CONVERT(VARCHAR,DATEPART(WEEK,[Start Date]))
    ,[Training Room]

您总是可以省略我按 ([Week Id]和[Training Room]) 分组的两个初始列的声明，因为您不必为了查看它们而显示它们。

于 2013-11-06T16:36:46.870 回答