1

我对以下代码有疑问 

public static void SideBet(int numberDice,int bet,int money) {
        System.out.println("You established a " + "\""+ "point" + "\"" + ". " + "Your " + "\""+ "point" + "\"" + " is " + numberDice + ". " + "You have to roll a(n) " + numberDice + " to win your bet, "+ bet +" chips." );

        System.out.println();
        System.out.println("You can put side bets for 4,5,6,8,9 or 10.");
        SideBetChoice = Console.readLine("Would you like to make any side bets ? (Type " + "\""+ "Yes" + "\"" + " or "+ "\""+ "No" + "\"" + ", then hit Enter.)");

        int s = 0;
        int r = 0;

           if (SideBetChoice.equals("Yes")) {
                System.out.println("You can put as many side bets as you would like for the numbers 4,5,6,8,9 or 10.");
                int SideBetNumber = Console.readInt("How many side bets would you like to make ? (Introduce a number, minimum 1, maximum 6.)");

                int[] SBNArray = new int[SideBetNumber];
                int[] sbArray = new int[SideBetNumber];


                    for (s = 0; s <= (SideBetNumber -1) ; s++) {
                       SBNArray[s] = Console.readInt("On which number would you like to put a side bet ?");
                       sbArray[s] = Console.readInt("Currently you have " + money + " chips, how much would you like to bet ?");
                       money = money - sbArray[s];
                       System.out.println("Thank you for your " +sbArray[s]+ " chip side bet on number " +SBNArray[s]+".");
                       System.out.println();
                    }

           } 
           if (SideBetChoice.equals("No")) {
                return;
           }

sbArray 和 SBNArray 没有得到一个值，它一直在崩溃......谁能帮我，告诉我出了什么问题，为什么 2 个数组没有得到一个值，因此它们是 null ？

4

1 回答 1

0

控制台中没有 readInt() 方法。另外我不确定您是否正确使用控制台，它应该如下所示：

Console console = System.console();

console.readLine("Type something");

只需使用 readLine() 并将其转换为 int：

    Console console = System.console();

    String input = console.readLine("Type a number");
    try
    {
        int myNumber = Integer.parseInt(input);
    }
    catch(NumberFormatException e)
    {
        System.out.println("This ain't a number!");
    }

也请不要在变量名或方法名中使用大写字母，这非常令人困惑，因为你可能认为它是一个类或一个类型。所以请更改 SBNArray 和 SideBetNumber、SideBetChoice 等的名称。只有常量应该只用大写字母编写，类和类型以大写字母开头。

编辑： 抱歉，您似乎正在使用 BreezyGUI.Console，因此有一个 readInt() 方法。

你能提供更多信息吗？我想知道是否显示了 readInt() 的文本。

于 2013-11-06T08:12:02.197 回答