java - 关于一个单词在java中拆分一个字符串

Question

如何将字符串说“懒惰的狗跑得快”与“狗”分开，以便我得到字符串 =“懒惰”、“狗”、“跑得快”？在爪哇

我正在使用的代码 String str="懒狗像狗一样奔跑"; 字符串狗=“狗”；String[] strArr= str.split(dog); for(int i=0;i

它返回：懒惰的人正在像一个

Answer 1

我建议使用正则表达式（和分组）。正则表达式几乎可以用来匹配你想要的任何东西！

例如

import java.util.regex.*;

public class PatternExample {

    public static void main(String[] args) {
        String split = "The Lazy dog is running fast";
        Pattern pattern = Pattern.compile("(.*)(dog)(.*)");
        Matcher matcher = pattern.matcher(split);
        while (matcher.find()) {
            for (int i = 0; i <= matcher.groupCount(); i++){
                System.out.println(i + "->" + matcher.group(i));
            }
        }
    }
}

给出：

0->The Lazy dog is running fast
1->The Lazy 
2->dog
3-> is running fast

采取2：没有正则表达式

public class PatternExample {

    public static void main(String[] args) {
        String split = "The Lazy dog is running fast";
        String word = "dog";
        String tmp = split;
        while (tmp.contains(word)){
            int x = tmp.indexOf(word);
            System.out.println(tmp.substring(0,x));
            System.out.println(word);
            tmp = tmp.substring(x+word.length());
        }
        System.out.println(tmp);
    }
}

Answer 2

我希望我正确理解了您的问题，如果是这样，这就是我将如何开始，您仍然需要填补边缘情况的空白。可以用substringandindexOf代替split，但不使用似乎太方便了。

package test;


public class Main {
    public static void main(String[] args) {
        String sentence = "The Lazy dog is running fast";
        String word = "dog";
        String[] splitByWord = splitByWord(word, sentence);
        for (String string : splitByWord) {
            System.out.println(string);
        }

    }

    public static String[] splitByWord(String word, String sentence) {
        String[] split = sentence.split(" " + word + " ");
        //TODO: handle edge cases where word is not found in sentence, or first word, or last
        return new String[]{split[0], word, split[1]};
    }
}