2

我正在使用上传插件 2.0 josegonzalez。Cakephp 的图像上传器，效果非常好。

但是我遇到了一个问题，我可以使用createWithAttachments插件的一部分。
一切都很好，除了一件事。我不想在上传新附件（照片）时创建新项目（ID、名称等）。

一个项目有更多的附件（照片），用户可以为每个项目上传总共 10 张照片。

来自Project.php （模型）的代码

<?php
    class Project extends AppModel {
      /* the rest of your model here */

      public function createWithAttachments($data) {
        // Sanitize your images before adding them
        $images = array();
        if (!empty($data['Image'][0])) {
          foreach ($data['Image'] as $i => $image) {
            if (is_array($data['Image'][$i])) {
              // Force setting the `model` field to this model
              $image['model'] = 'Project';

              $images[] = $image;
            }
          }
        }
        $data['Image'] = $images;

        // Try to save the data using Model::saveAll()
        $this->create();
        if ($this->saveAll($data)) {
          return true;
        }

        // Throw an exception for the controller
        throw new Exception(__("This post could not be saved. Please try again"));
      }
    } 
?>

来自ProjectsController.php （控制器）的代码

<?php
    class ProjectsController extends AppController {
      /* the rest of your controller here */
      public function cms_album() {
        if ($this->request->is('post')) {
          try {
            $this->Project->createWithAttachments($this->request->data);
            $this->Session->setFlash(__('The message has been saved'));
          } catch (Exception $e) {
            $this->Session->setFlash($e->getMessage());
          }
        }
      }
    } 
?>

每次我向数据库表中添加 10 张照片时，它都会在数据库表attachments中创建一个新项目projects。我只希望附件是新的，并保存我从表单部分获得的项目的 IDecho $this->Form->input('Image.'.$i.'.foreign_key', array('type' => 'hidden', 'value' => ''.$this->params->pass[0].''));

我希望我清楚地写出了我的问题，并且有人可以帮助我。我尝试了很多事情，甚至试图用一个AttachmentsController （没有运气）来完成

更新：（在Anil kumar的 awnser 之后）

这是一个print_r在$data它使用之前if($this->saveAll($data))

Array
(
    [Image] => Array
        (
            [0] => Array
                (
                    [model] => Project
                    [foreign_key] => 7
                    [attachment] => Array
                        (
                            [name] => DSCN4923.JPG
                            [type] => image/jpeg
                            [tmp_name] => /tmp/phpGbIKTl
                            [error] => 0
                            [size] => 141994
                        )    
                )    
            [1] => Array
                (
                    [model] => Project
                    [foreign_key] => 7
                    [attachment] => Array
                        (
                            [name] => DSCN4921.JPG
                            [type] => image/jpeg
                            [tmp_name] => /tmp/phpJBeYxk
                            [error] => 0
                            [size] => 216931
                        )    
                )    
            [2] => Array
                (
                    [model] => Project
                    [foreign_key] => 7
                    [attachment] => Array
                        (
                            [name] => DSCN3810.JPG
                            [type] => image/jpeg
                            [tmp_name] => /tmp/phpR6sflk
                            [error] => 0
                            [size] => 1304426
                        )
                )
        )
)
4

2 回答 2

2

$this->create();在您的项目模型中删除，

并确保$data不包含与项目相关的任何数据$this->saveAll($data);

The "saveAll" function is just a wrapper around the "saveMany" and "saveAssociated" methods.

所以它会保存模型数据以及相关的模型数据，最好使用$this->Image->saveMany($data)而不是 $this->saveAll($data)

有关更多信息，请检查saveAll。

更新

只需评论这些行。

// $this->create();
// if ($this->saveAll($data)) {
//   return true;
// }

并将上面的内容替换为

if ($this->Image->saveMany($data)) {
    return true;
}
于 2013-11-13T14:52:37.010 回答
1

要添加新的关联记录，您需要指定要添加内容的项目的 ID：

<?php
    class Project extends AppModel {
      /* the rest of your model here */

      public function createWithAttachments($data) {
        $data['Image'] = $this->sanitizeImages($data);

        // Try to save the data using Model::saveAll()
        $this->create();
        if ($this->saveAll($data)) {
          return true;
        }

        // Throw an exception for the controller
        throw new Exception(__("This post could not be saved. Please try again"));
      }

      public function addAttachments($data) {
        $data['Image'] = $this->sanitizeImages($data);

        // Make sure you have and id on $this-id and Try to save the data
        if ($this->getID() && $this->Image->save($data)) {
          return true;
        }

        // Throw an exception for the controller
        throw new Exception(__("This post could not be saved. Please try again"));
      }

      private function sanitizeImages($data) {
        // Sanitize your images before adding them
        $images = array();
        if (!empty($data['Image'][0])) {
          foreach ($data['Image'] as $i => $image) {
            if (is_array($data['Image'][$i])) {
              // Force setting the `model` field to this model
              $image['model'] = 'Project';

              $images[] = $image;
            }
          }
        }

        return $images;
      }
    }

?>

在你的控制器中你可以做

 $this->Project->id = $id;
 $this->Project->addAttachments($data);

我不是 100% 确定代码会起作用，它只是为了让您了解需要做什么。

另一个解决方案是在数据中发送项目 ID。

Array
(
    [Project] => Array(
        [id] => 1 //Here goes the id of the project you would like to add attachments to
    ),
    [Image] => Array
        (
            [0] => Array
                (
                    [model] => Project
                    [foreign_key] => 7
                    [attachment] => Array
                        (
                            [name] => DSCN4923.JPG
                            [type] => image/jpeg
                            [tmp_name] => /tmp/phpGbIKTl
                            [error] => 0
                            [size] => 141994
                        )    
                )    
            [1] => Array
                (
                    [model] => Project
                    [foreign_key] => 7
                    [attachment] => Array
                        (
                            [name] => DSCN4921.JPG
                            [type] => image/jpeg
                            [tmp_name] => /tmp/phpJBeYxk
                            [error] => 0
                            [size] => 216931
                        )    
                )    
            [2] => Array
                (
                    [model] => Project
                    [foreign_key] => 7
                    [attachment] => Array
                        (
                            [name] => DSCN3810.JPG
                            [type] => image/jpeg
                            [tmp_name] => /tmp/phpR6sflk
                            [error] => 0
                            [size] => 1304426
                        )
                )
        )
)
于 2013-11-13T18:11:52.083 回答