嗯,基本上我对 PHP 比较陌生,我一直在尝试教程(请参阅下面的链接),但我不断收到错误,我用谷歌搜索了它,但似乎没有任何效果:S
我使用 Chrome 时遇到的错误是:此页面包含以下错误:第 1 行第 3 列的错误:xmlParsePI:没有目标名称下面是页面的呈现,直到第一个错误。
教程:https ://developers.google.com/maps/articles/phpsqlsearch_v3
这是代码:
<?php
require("phpsqlsearch_dbinfo.php");
// Get parameters from URL
// Get parameters from URL
$center_lat = ( isset( $_GET["lat"] ) ? $_GET["lat"] : 37 );
$center_lng = ( isset( $_GET["lng"] ) ? $_GET["lng"] : 122 );
$radius = ( isset( $_GET["radius"] ) ? $_GET["radius"] : 25 );
// Start XML file, create parent node
$dom = new DOMDocument("1.0");
$node = $dom->createElement("markers");
$parnode = $dom->appendChild($node);
// Opens a connection to a mySQL server
$connection=mysql_connect ('localhost', 'root', '');
if (!$connection) {
die("Not connected : " . mysql_error());
}
// Set the active mySQL database
$db_selected = mysql_select_db('test', $connection);
if (!$db_selected) {
die ("Can\'t use db : " . mysql_error());
}
// Search the rows in the markers table
$query = sprintf("SELECT address, name, lat, lng, ( 3959 * acos( cos( radians('%s') ) * cos( radians( lat ) ) * cos( radians( lng ) - radians('%s') ) + sin( radians('%s') ) * sin( radians( lat ) ) ) ) AS distance FROM markers HAVING distance < '%s' ORDER BY distance LIMIT 0 , 20",
mysql_real_escape_string($center_lat),
mysql_real_escape_string($center_lng),
mysql_real_escape_string($center_lat),
mysql_real_escape_string($radius));
$result = mysql_query($query);
if (!$result) {
die("Invalid query: " . mysql_error());
}
header("Content-type: text/xml");
// Iterate through the rows, adding XML nodes for each
while ($row = @mysql_fetch_assoc($result)){
$node = $dom->createElement("marker");
$newnode = $parnode->appendChild($node);
$newnode->setAttribute("name", $row['name']);
$newnode->setAttribute("address", $row['address']);
$newnode->setAttribute("lat", $row['lat']);
$newnode->setAttribute("lng", $row['lng']);
$newnode->setAttribute("distance", $row['distance']);
}
echo $dom->saveXML();
?>
有人可以帮忙吗?