基于 URL
querydict = {customer_type:val1,tag:[], city:[],last_contact:valdate}
show/?customer_type=All&tag=2,3&city=3&last_contact=29/12/2009
我将通过制作方法进行过滤:
def get_filter_result(customer_type, tag_selected, city_selected, last_contact_filled):
if customer_type=has value:
I filter by this
#queryset = Customer.objects.filter(Q(type__name=customer_type))
if tag = has value :
I filter by this
#queryset = Customer.objects.filter(Q(type__name=customer_type)
Q(type__name=tag))
if city = has value:
I filter by this
#queryset = Customer.objects.filter(Q(type__name=customer_type)
Q(type__name=tag),
Q(type__name=city))
if last_contact = has value:
I filter by this
#queryset = Customer.objects.filter(Q(type__name=customer_type)
Q(type__name=tag),
Q(type__name=city),
Q(type__name=last_contact))
有人帮忙给出一个想法来实现我的方法比这更简单和灵活吗?如果它们的值丢失或等于无(没有传递值)所以如果......否则......条件将控制很多时间并且代码会更大..
for example :
show/?customer_type=All&tag=&city=&last_contact=
show/?customer_type=All&tag=2,3&city=3&last_contact=29/12/2009
show/?customer_type=&tag=2,3&city=3&last_contact=
show/?customer_type=All&tag=2,3&city=&last_contact=29/12/2009
谢谢