有没有办法按打开任务的数量排序?
SELECT Tasks.ClientName, Count(*) AS OpenTaskCount
FROM Tasks
WHERE (((Tasks.Completed)=False))
GROUP BY Tasks.ClientName
ORDER BY OpenTaskCount DESC;
当我尝试这个时,它会在 GUI 中提示 OpenTaskCount。
有没有办法按打开任务的数量排序?
SELECT Tasks.ClientName, Count(*) AS OpenTaskCount
FROM Tasks
WHERE (((Tasks.Completed)=False))
GROUP BY Tasks.ClientName
ORDER BY OpenTaskCount DESC;
当我尝试这个时,它会在 GUI 中提示 OpenTaskCount。
尝试这个:
SELECT Tasks.ClientName, Count(*) AS OpenTaskCount
FROM Tasks
WHERE (((Tasks.Completed)=False))
GROUP BY Tasks.ClientName
ORDER BY COUNT(*) DESC;
任何一个:
SELECT Tasks.ClientName, Count(*) AS OpenTaskCount
FROM Tasks
WHERE (((Tasks.Completed)=False))
GROUP BY Tasks.ClientName
ORDER BY Count(*) DESC;
或者
SELECT Tasks.ClientName, Count(*) AS OpenTaskCount
FROM Tasks
WHERE (((Tasks.Completed)=False))
GROUP BY Tasks.ClientName
ORDER BY 2 DESC;
应该管用。