0

需要在 foreach 中运行 2 个查询，但不能没有错误。

所以，我有这个来显示评论：

$query = 'SELECT * FROM comments WHERE updatepostid = "' . $postID . '"';
    try {
        $stmt = $db->prepare($query);
        $stmt->execute();
        $countcomments = $stmt->rowCount();
        }
        catch (PDOException $ex) 
        {
            die("Failed to run query: " . $ex->getMessage());
        }

$rows = $stmt->fetchAll();
foreach ($rows as $row):
$commentID       = $row['commentID'];
$usercommentID   = $row['userID'];
$commentusername = ucfirst($row['commentusername']);
$comment         = ucfirst($row['comment']);
$updatepostid    = $row['updatepostid'];

<div class="textcomment">
    <?php
        echo "<a class='$rightscommentcolor'>$commentusername:</a>&nbsp; $comment";
    ?>
</div>


<?php endforeach; ?>

然后，我想在用户数据库上运行另一个查询以检查用户拥有什么权限，然后将评论用户名的类设置为该类。

该查询将是例如

    <?php

$query2 = 'SELECT * FROM users WHERE id = "' . $usercommentID . '"';
    try {
        $stmt = $db->prepare($query2);
        $stmt->execute();
        }
        catch (PDOException $ex) 
        {
            die("Failed to run query: " . $ex->getMessage());
        }

$rows = $stmt->fetchAll();
foreach ($rows as $row):
$rights = $row['rights'];

if ($rights = '1') {
    $rightscommentcolor = 'userrights1';
} else if ($rights = '5') {
    $rightscommentcolor = 'userrights5';
}

?>
<?php endforeach; ?>

正确的方法是如何解决这个问题？

PS我明白上面的代码可能会让人们哭泣。

4

2 回答 2

4

使用带有连接的单个查询。此外，由于您使用的是 PDO，因此您应该使用参数化查询而不是连接字符串。

$query = "SELECT * FROM comments c
          JOIN users u ON u.id = c.userID
          WHERE updatepostid = :updatepostid";
try {
    $stmt = $db->prepare($query);
    $stmt->execute(array(':updatepostid' => $postID));
    }
catch (PDOException $ex) 
    {
        die("Failed to run query: " . $ex->getMessage());
    }
于 2013-11-04T22:19:39.527 回答
-2

如前所述，您可以在 select 中加入表格：

<?php

$query = "SELECT * FROM comments c
          JOIN users u ON u.usercommentID = c.userID
          WHERE updatepostid = :updatepostid";
    try {
        $stmt = $db->prepare($query);
        $stmt->execute();
        $countcomments = $stmt->rowCount();
        }
        catch (PDOException $ex) 
        {
            die("Failed to run query: " . $ex->getMessage());
        }

$rows = $stmt->fetchAll();
foreach ($rows as $row):

$commentID       = $row['commentID'];
$usercommentID   = $row['userID'];
$commentusername = ucfirst($row['commentusername']);
$comment         = ucfirst($row['comment']);
$updatepostid    = $row['updatepostid'];

if ($rights = '1') {
    $rightscommentcolor = 'userrights1';
} else if ($rights = '5') {
    $rightscommentcolor = 'userrights5';
}

echo "<div class="textcomment"><a class='$rightscommentcolor'>$commentusername:</a>&nbsp; $comment</div>";

endforeach;

?>

您还可以在第一个循环中插入第二个循环，并将单独的变量分配给第二个循环，这样它就不会与第一个循环冲突，如下所示，但加入将是一个更好的选择：

<?php

$query = 'SELECT * FROM comments WHERE updatepostid = "' . $postID . '"';
    try {
        $stmt = $db->prepare($query);
        $stmt->execute();
        $countcomments = $stmt->rowCount();
        }
        catch (PDOException $ex) 
        {
            die("Failed to run query: " . $ex->getMessage());
        }

$rows = $stmt->fetchAll();
foreach ($rows as $row):

$commentID       = $row['commentID'];
$usercommentID   = $row['userID'];
$commentusername = ucfirst($row['commentusername']);
$comment         = ucfirst($row['comment']);
$updatepostid    = $row['updatepostid'];

$query2 = 'SELECT * FROM users WHERE usercommentID = "' . $usercommentID . '"';
    try {
        $stmt2 = $db->prepare($query2);
        $stmt2->execute();
        }
        catch (PDOException $ex2) 
        {
            die("Failed to run query: " . $ex2->getMessage());
        }

$rows2 = $stmt2->fetchAll();
foreach ($rows2 as $row2):
$rights = $row2['rights'];

if ($rights = '1') {
    $rightscommentcolor = 'userrights1';
} else if ($rights = '5') {
    $rightscommentcolor = 'userrights5';
}

endforeach;

echo "<div class="textcomment"><a class='$rightscommentcolor'>$commentusername:</a>&nbsp; $comment</div>";

endforeach;

?>
于 2013-11-04T22:22:22.657 回答