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我正在尝试完成 CodeIgniter 教程，我的新闻页面不会从 foreach 循环输出数据。我收到以下消息：

A PHP Error was encountered

Severity: Notice

Message: Undefined variable: news

Filename: pages/index.php

Line Number: 1

和

A PHP Error was encountered

Severity: Warning

Message: Invalid argument supplied for foreach()

Filename: pages/index.php

Line Number: 1

这是我的模型课：

<?php
class News_model extends CI_Model {

public function __construct()
{
    $this->load->database();
}


public function get_news($slug = FALSE)
{
if ($slug === FALSE)
{
    $query = $this->db->get('news');
    return $query->result_array();
}

$query = $this->db->get_where('news', array('slug' => $slug));
return $query->row_array();
}


public function index()
{
$data['news'] = $this->news_model->get_news();
$data['title'] = 'News archive';

$this->load->view('templates/header', $data);
$this->load->view('news/index', $data);
$this->load->view('templates/footer');
}
}

我的控制器：

class News extends CI_Controller {

public function __construct()
{
    parent::__construct();
    $this->load->model('news_model');
}

public function index()
{
    $data['news'] = $this->news_model->get_news();
}


public function view($slug)
{
    $data['news_item'] = $this->news_model->get_news($slug);

    if (empty($data['news_item']))
    {
        show_404();
    }

    $data['title'] = $data['news_item']['title'];

    $this->load->view('templates/header', $data);
    $this->load->view('news/view', $data);
    $this->load->view('templates/footer');
}

}

第一种观点： 

    <h2><?php echo $news_item['title'] ?></h2>
    <div id="main">
        <?php echo $news_item['text'] ?>
    </div>
    <p><a href="news/<?php echo $news_item['slug'] ?>">View article</a></p>

<?php endforeach ?>

第二个：

<?php
echo '<h2>'.$news_item['title'].'</h2>';
echo $news_item['text'];

我知道关于本教程还有其他问题，但似乎没有一个对我有帮助。

谢谢。

4

1 回答 1

1

在模型中，您在构造函数之后关闭了您的类。应在所有功能后关闭。view() 也被初始化了两次。

于 2013-11-04T18:41:20.957 回答