我正在做 UVa 问题 10082,我正在尝试读取一些示例输入来测试我的解决方案。但是,当我阅读文本时'''CCC
,它会输出;;XXX
. 请注意,只有 2 个分号,而应该有 3 个,因为输入中有 3 个单引号。为什么 getline() 忽略第一个单引号?
这是我的代码:
#include <iostream>
#include <string>
using namespace std;
char mapToWertyu(char c)
{
char newC = c;
char wertyu[] = {'1','2','3','4','5','6','7','8','9','0','-','=',
'Q','W','E','R','T','Y','U','I','O','P','[',']','\\',
'A','S','D','F','G','H','J','K','L',';','\'',
'Z','X','C','V','B','N','M',',','.','/'};
char qwerty[] = {'~','1','2','3','4','5','6','7','8','9','0','-','=',
'Q','W','E','R','T','Y','U','I','O','P','[',']','\\',
'A','S','D','F','G','H','J','K','L',';','\'',
'Z','X','C','V','B','N','M',',','.','/'};
if(c=='A' || c=='Q' || c=='Z')
return c;
for(int i = 0; i < 47; ++i)
{
if(wertyu[i]==c)
{
newC = qwerty[i];
break;
}
}
return newC;
}
int main()
{
string input;
while(cin.peek()!=-1)
{
getline(cin,input);
for(int i = 0; i < input.length(); ++i)
{
if(input[i]!='\\')
cout << mapToWertyu(input[i]);
}
cin.ignore(1,'\n');
cout << endl;
}
return 0;
}