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此任务是从游戏角色中确定力量和技能这两个属性之间的差异。这个过程是：

  • 确定强度属性之间的差异。
  • 差值除以五并向下舍入以创建“强度修正”。
  • 对技能属性执行相同的过程并命名为“技能修饰符”。
  • 然后游戏开始：
    • 两名玩家都掷出一个六面骰子。
    • 如果值相同，则不会发生任何变化。
    • 如果值不同，则具有最高值的玩家获得先前计算的力量和技能，然后将其添加到他们的总数中。具有最低值的玩家的力量和技能从他们的总数中扣除。

这必须重复，直到强度属性等于或低于 0，但是，这部分我不能做，我知道如何循环，但这总是通过询问用户是否希望再去来完成。

c1sc=random.randint(1,6)
c2sc=random.randint(1,6)
if c1sc > c2sc:
    c1st=c1st+strengthmodifier
    c2st=c2st-strengthmodifier
    c1sk=c1sk+skillmodifier
    c2sk=c2sk-skillmodifier
    print('Character 1, your strength attribute is: '+(str(c1st))+' and your skill attribute is: '+(str(c1sk)))
    print('Character 2, your strength attribute is: '+(str(c2st))+' and your skill attribute is: '+(str(c2sk)))
elif c2sc > c1sc:
    c1st=c1st-strengthmodifier
    c2st=c2st+strengthmodifier
    c1sk=c1sk-skillmodifier
    c2sk=c2sk+skillmodifier
    print('Character 1, your strength attribute is: '+(str(c1st))+' and your skill attribute is: '+(str(c1sk)))
    print('Character 2, your strength attribute is: '+(str(c2st))+' and your skill attribute is: '+(str(c2sk)))
else:
    print('It\'s a draw, no changes were made.')
if c1sk < 0:
    c1sk=0
elif c2sk < 0:
    c2sk=0

if c1st < 0:
    print('Character 1 died. Game over.')
elif c2st < 0:
    print('Character 2 died. Game over.')

请帮忙！

4

3 回答 3

1

让我给你介绍一下while循环。如果指定条件为真或假，您希望某事发生时使用此选项。

我简要编辑了您的代码。

随机导入

def main():
 player1=20
 player2=12
 strength=(20-10)/5
 strength_mod=int(strength)
 while player1>0 and player2>0:
  dice1=random.randint(1,6)
  dice2=random.randint(1,6)
  if dice1>dice2:
    player1+=strength_mod
    player2-=strength_mod
    print("Player 1 strength is:  ", player1)
    print("Player 2 strength is:  ", player2)
  elif dice1<dice2:
    player2+=strength_mod
    player1-=strength_mod
    print("Player 1 strength is:  ", player1)
    print("Player 2 strength is:  ", player2)

main()

我给玩家 1 和 2 初始值打赌这些可以更改为您的喜好。为了向下取整，我制作了另一个变量并将强度更改为整数。

于 2013-11-04T18:49:06.973 回答
0

添加另一个循环来减少...

c1sc=random.randint(1,6)
c2sc=random.randint(1,6)
if c1sc > c2sc:
    while c2st > 0 and c2sk > 0:
        c1st=c1st+strengthmodifier
        c2st=c2st-strengthmodifier
        c1sk=c1sk+skillmodifier
        c2sk=c2sk-skillmodifier
        print('Character 1, your strength attribute is: '+(str(c1st))+' and your skill attribute is: '+(str(c1sk)))
        print('Character 2, your strength attribute is: '+(str(c2st))+' and your skill attribute is: '+(str(c2sk)))
elif c2sc > c1sc:
    while c1st > 0 and c1sk > 0:
        c1st=c1st-strengthmodifier
        c2st=c2st+strengthmodifier
        c1sk=c1sk-skillmodifier
        c2sk=c2sk+skillmodifier
        print('Character 1, your strength attribute is: '+(str(c1st))+' and your skill attribute is: '+(str(c1sk)))
        print('Character 2, your strength attribute is: '+(str(c2st))+' and your skill attribute is: '+(str(c2sk)))
else:
    print('It\'s a draw, no changes were made.')
if c1sk < 0:
    c1sk=0
elif c2sk < 0:
    c2sk=0

if c1st < 0:
    print('Character 1 died. Game over.')
elif c2st < 0:
    print('Character 2 died. Game over.')

当然，还有更简洁的写法。这仍然不理想，但减少了代码......

c1sc=random.randint(1,6)
c2sc=random.randint(1,6)
if c1sc != c2sc:
    while c1st > 0 and and c2st > 0:
        c1st += strengthmodifier if c1sc > c2sc else -1 * strengthmodifier
        c2st += strengthmodifier if c1sc < c2sc else -1 * strengthmodifier
        c1sk += skillmodifier if c1sc > c2sc else -1 * skillmodifier
        c2sk += skillmodifier if c1sc < c2sc else -1 * skillmodifier
        print('Character 1, your strength attribute is: '+(str(c1st))+' and your skill attribute is: '+(str(c1sk)))
        print('Character 2, your strength attribute is: '+(str(c2st))+' and your skill attribute is: '+(str(c2sk)))
    c1sk = math.max(c1sk, 0) # Clamp skill to a minimum of 0
    c2sk = math.max(c2sk, 0) # ...

    if c1st < c2st:
        print('Character 1 died. Game over.')
    else:
        print('Character 2 died. Game over.')
else:
    print('It\'s a draw, no changes were made.')

最后，假设每轮都重​​新掷骰子......

while c1st > 0 and and c2st > 0:
    c1sc=random.randint(1,6)
    c2sc=random.randint(1,6)
    if c1sc != c2sc:
        c1st += strengthmodifier if c1sc > c2sc else -1 * strengthmodifier
        c2st += strengthmodifier if c1sc < c2sc else -1 * strengthmodifier
        c1sk += skillmodifier if c1sc > c2sc else -1 * skillmodifier
        c2sk += skillmodifier if c1sc < c2sc else -1 * skillmodifier
        print('Character 1, your strength attribute is: '+(str(c1st))+' and your skill attribute is: '+(str(c1sk)))
        print('Character 2, your strength attribute is: '+(str(c2st))+' and your skill attribute is: '+(str(c2sk)))
    else:
        print('It\'s a draw, no changes were made.')


    c1sk = math.max(c1sk, 0) # Clamp skill to a minimum of 0
    c2sk = math.max(c2sk, 0) # ...

if c1st < c2st:
    print('Character 1 died. Game over.')
else:
    print('Character 2 died. Game over.')
于 2013-11-04T17:38:14.880 回答
0

就这样你得到图片：（在伪代码中）

while (c2sk > 0 && c1sk > 0)
    //do complete everything up until the if statements
if c1st <0
    print "c1st died" 
elif c2st <0
    print "c2st died"

不确定这是否正是您要寻找的。如果 c2sk 和 c1sk 应该在每次它应该在循环内时被随机重新分配。

于 2013-11-04T17:39:20.987 回答