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我不完全了解 yii 框架。如何为这种情况制定 CDbCriteria?我有一个这样的基本查询代码。

SELECT
jam_kerja.id,
jam_kerja.id_cabang,
jam_kerja.tgl_berlaku,
jam_kerja_detail.id_jam_kerja,
jam_kerja_detail.shift,
jam_kerja_detail.jamkerja,
jam_kerja_detail.jamistirahat
FROM
jam_kerja ,
jam_kerja_detail
WHERE
jam_kerja_detail.id_jam_kerja =  jam_kerja.id and  jam_kerja.id_cabang=5

也许有Yii朋友可以帮助我?

4

2 回答 2

0

我终于找到了解决方案,它可能对其他朋友有用。

$criteria=new CDbCriteria;
$criteria->join='INNER JOIN jam_kerja t1 ON t1.id=t.id_jam_kerja';
$criteria->condition='t1.id_cabang='.$_GET['id'];
于 2013-11-08T07:09:32.300 回答
0
$criteria = new CDbCriteria();
$criteria->select = 't.id,t.id_cabang, t.tgl_berlaku, jd.id_jam_kerja, jd.shift ,jd.jamkerja,';

$criteria->join = 'INNER JOIN jam_kerja_detail jd ON t.id = jd.id_jam_kerja'; 

$criteria->addCondition('t.id_cabang=5'); // edited this line

//and now give this criteria to your model

$model = YourModel::model()->findAll($criteria);
于 2013-11-04T09:08:21.133 回答